如何将数据库中的数据显示到文本框中,并进行更新

时间:2013-01-01 18:23:12

标签: c# asp.net sql-server-2008

我可以在从sql数据库中检索数据后在我的文本框,下拉列表中显示我的数据,但是当我继续我的更新按钮时,在文本框或下拉列表中编辑的信息将不会更新到数据库中。我试图删除页面加载中的代码,并手动重新键入所有数据,它可以更新。我想要的只是从数据库中检索数据并将其显示在文本框中,并且可以在从文本框进行一些更改后更新到数据库中。有人可以帮我吗?感谢。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data.SqlClient;
using System.Configuration;
using System.Data;
public partial class UpdateCustomerDetails : System.Web.UI.Page
{

protected void Page_Load(object sender, EventArgs e)
{
    SqlConnection con1 = new SqlConnection("Data Source=USER-PC;Initial Catalog=webservice_database;Integrated Security=True");
    DataTable dt = new DataTable();
    con1.Open();
    SqlDataReader myReader = null;  
    SqlCommand myCommand = new SqlCommand("select * from customer_registration where username='" + Session["username"] + "'", con1);

    myReader = myCommand.ExecuteReader();

    while (myReader.Read())
    {
        TextBoxPassword.Text = (myReader["password"].ToString());
        TextBoxRPassword.Text = (myReader["retypepassword"].ToString());
        DropDownListGender.SelectedItem.Text = (myReader["gender"].ToString());
        DropDownListMonth.Text = (myReader["birth"].ToString());
        DropDownListYear.Text = (myReader["birth"].ToString());
        TextBoxAddress.Text = (myReader["address"].ToString());
        TextBoxCity.Text = (myReader["city"].ToString());
        DropDownListCountry.SelectedItem.Text = (myReader["country"].ToString());
        TextBoxPostcode.Text = (myReader["postcode"].ToString());
        TextBoxEmail.Text = (myReader["email"].ToString());
        TextBoxCarno.Text = (myReader["carno"].ToString());
    }
    con1.Close();
}
protected void Button1_Click(object sender, EventArgs e)
{
    SqlConnection con = new SqlConnection("Data Source=USER-PC;Initial Catalog=webservice_database;Integrated Security=True");
    SqlCommand cmd = new SqlCommand("UPDATE customer_registration SET password = @password, retypepassword = @retypepassword, gender = @gender, birth = @birth, address = @address, city = @city, country = @country, postcode = @postcode, email = @email, carno = @carno where username='" + Session["username"] + "'", con);
    con.Open();

    cmd.Parameters.AddWithValue("@password", TextBoxPassword.Text);
    cmd.Parameters.AddWithValue("@retypepassword", TextBoxRPassword.Text);
    cmd.Parameters.AddWithValue("@gender", DropDownListGender.Text);
    cmd.Parameters.AddWithValue("@birth", DropDownListDay.Text + DropDownListMonth.Text + DropDownListYear.Text);
    cmd.Parameters.AddWithValue("@address", TextBoxAddress.Text);
    cmd.Parameters.AddWithValue("@city", TextBoxCity.Text);
    cmd.Parameters.AddWithValue("@country", DropDownListCountry.Text);
    cmd.Parameters.AddWithValue("@postcode", TextBoxPostcode.Text);
    cmd.Parameters.AddWithValue("@email", TextBoxEmail.Text);
    cmd.Parameters.AddWithValue("@carno", TextBoxCarno.Text);

    cmd.ExecuteNonQuery();
    con.Close();
    if (IsPostBack)
    {
        Response.Redirect("UpdateSuccess.aspx");
    }
}

4 个答案:

答案 0 :(得分:4)

在页面加载时以!IsPostBack条件包装所有语句。

protected void Page_Load(object sender, EventArgs e)
{
   if(!IsPostBack)
   {
      // all statements
   }
}

这将解决您的问题。

答案 1 :(得分:1)

protected void Page_Load(object sender, EventArgs e)

    {

        DropDownTitle();
    }


protected void DropDownTitle()
{
    if (!Page.IsPostBack)
    {

        string connection = System.Configuration.ConfigurationManager.ConnectionStrings["AuzineConnection"].ConnectionString;

        string selectSQL = "select DISTINCT ForumTitlesID,ForumTitles from ForumTtitle";
        SqlConnection con = new SqlConnection(connection);
        SqlCommand cmd = new SqlCommand(selectSQL, con);
        SqlDataReader reader;
        try
        {

            ListItem newItem = new ListItem();
            newItem.Text = "Select";
            newItem.Value = "0";
            ForumTitleList.Items.Add(newItem);
            con.Open();
            reader = cmd.ExecuteReader();



            while (reader.Read())
            {
                ListItem newItem1 = new ListItem();
                newItem1.Text = reader["ForumTitles"].ToString();
                newItem1.Value = reader["ForumTitlesID"].ToString();
                ForumTitleList.Items.Add(newItem1);



            }
            reader.Close();
            reader.Dispose();
            con.Close();
            con.Dispose();
            cmd.Dispose();


        }
        catch (Exception ex)
        {
            Response.Write(ex.Message);
        }

    }
}

答案 2 :(得分:0)

答案是.IsPostBack,正如@Kundan Singh Chouhan所建议的那样。只需添加它,将代码移到与Page_Load

不同的方法中
private void PopulateFields()
{
  using(SqlConnection con1 = new SqlConnection("Data Source=USER-PC;Initial Catalog=webservice_database;Integrated Security=True"))
  {
    DataTable dt = new DataTable();
    con1.Open();
    SqlDataReader myReader = null;  
    SqlCommand myCommand = new SqlCommand("select * from customer_registration where username='" + Session["username"] + "'", con1);

    myReader = myCommand.ExecuteReader();

    while (myReader.Read())
    {
        TextBoxPassword.Text = (myReader["password"].ToString());
        TextBoxRPassword.Text = (myReader["retypepassword"].ToString());
        DropDownListGender.SelectedItem.Text = (myReader["gender"].ToString());
        DropDownListMonth.Text = (myReader["birth"].ToString());
        DropDownListYear.Text = (myReader["birth"].ToString());
        TextBoxAddress.Text = (myReader["address"].ToString());
        TextBoxCity.Text = (myReader["city"].ToString());
        DropDownListCountry.SelectedItem.Text = (myReader["country"].ToString());
        TextBoxPostcode.Text = (myReader["postcode"].ToString());
        TextBoxEmail.Text = (myReader["email"].ToString());
        TextBoxCarno.Text = (myReader["carno"].ToString());
    }
    con1.Close();
  }//end using
}

然后在你的Page_Load

中调用它
protected void Page_Load(object sender, EventArgs e)
{

    if(!Page.IsPostBack)
    {
       PopulateFields();
    }
}

答案 3 :(得分:0)

填充Page Init事件中的文本框值,而不是使用Postback。

protected void Page_Init(object sender, EventArgs e)
{
    DropDownTitle();
}