Question

我正在尝试使用python发送邮件，在变量“body”中保存正文我尝试使用下面解密它但是电子邮件的正文保持原样，html代码没有得到解码..我查看了其他帖子在stackoverflow上，但无法获得任何实质性的......哪里出错了？

from email.mime.text import MIMEText
from subprocess import Popen, PIPE

def email (body,subject):
    msg = MIMEText("%s" % body)
    msg["From"] = "test@company.com"
    msg["To"] = "bot@qualcomm.com"
    msg["Subject"] = 'The contents of %s' % subject
    p = Popen(["/usr/sbin/sendmail", "-t"], stdin=PIPE)
    p.communicate(msg.as_string())
def main ():
    subject="Test subject"
    body = """\
        <html>
         <head></head>
         <body>
          <p>Hi!<br>
              How are you?<br>
             Here is the <a href="http://www.python.org">link</a> you wanted.
         </p>
         </body>
        </html>
"""
    email(body,subject)

if __name__ == '__main__':
    main()

正在按照以下方式打印正文...原始代码未被解码

<html>
 <head></head>
 <body>
  <p>Hi!<br>
      How are you?<br>
     Here is the <a href="http://www.python.org">link</a> you wanted.
 </p>
 </body>
</html>

Answer 1

哦......所以你希望MUA将内容解释为html。在消息中设置内容类型：

msg["Content-Type"] = "text/html"

否则，MUA将假设它为text/plain，并将其渲染为此类。

发送电子邮件时解密正文

1 个答案: