查询不等于多个值

Question

我有这方面的编码，有人可以帮助我使查询正确，我以为我有它但我只是收到一个查询错误
原始代码：

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 $myf ORDER BY level DESC,userid ASC LIMIT 20");

我的编辑代码失败：

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 || WHERE u.user_level !=0 $myf ORDER BY level DESC,userid ASC LIMIT 20");

Answer 1

使用此

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 || u.user_level !=0 $myf ORDER BY level DESC,userid ASC LIMIT 20");

你不能把两个放在Clause

仅供参考：http://dev.mysql.com/doc/refman/5.0/en//select.html

Answer 2

代替

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 || WHERE u.user_level !=0 $myf ORDER BY level DESC,userid ASC LIMIT 20");

你应该，（删除第二位）

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 || u.user_level !=0 $myf ORDER BY level DESC,userid ASC LIMIT 20");