Question

我有一张桌子如下。

我想在单一查询中获得最低，最高和平均成本产品的product_id。

CREATE TABLE productlist(product_id INT NOT NULL PRIMARY KEY AUTO_INCREMENT,
                         cost INT);                             

INSERT INTO productlist(cost)
                 VALUES('2450'),
                       ('2200'),
                       ('2580'),
                       ('2405'),
                       ('3500'),
                       ('1500'),
                       ('1800'),
                       ('1520'),
                       ('1740'),
                       ('1940'),
                       ('2940'),
                       ('1250'),
                       ('1290'),
                       ('1390'),
                       ('2900');

输出：

Min    12
Max    5
Avg    2093

我尝试了下面的一个，但它不起作用。

SELECT product_id, MIN(cost) as mincost
  FROM productlist
 GROUP BY product_id
 ORDER BY mincost ASC
 LIMIT 0,1
 UNION
SELECT product_id, max(cost) as maxcost
  FROM productlist
 GROUP BY product_id
 ORDER BY maxcost DESC
 LIMIT 0,1

我该怎么做

Answer 1

select product_id, cost
from productlist where cost = (SELECT max(cost)from productlist)
union
select product_id, cost
from productlist where cost = (SELECT min(cost)from productlist)
union
select product_id, cost
from productlist where cost = (SELECT x.cost from productlist x, productlist y
GROUP BY x.cost
HAVING SUM(SIGN(1-SIGN(y.cost-x.cost))) = (COUNT(*)+1)/2)

这使用中位数，在每种情况下返回产品ID

Answer 2

select 'Min', product_id 
from productlist
where cost = (select min(cost) from productlist)
UNION 
select 'Max', product_id
from productlist
where cost = (select MAX(cost) from productlist)
UNION 
select 'Avg', round(AVG(cost),0) as Avg
from productlist

Answer 3

这是为了选择所有产品

  SELECT 
          max(cost), MIN(cost), AVG(cost)
    FROM 
          productlist
    GROUP BY
          product_id

此处并不完全需要GROUP BY。但看起来你是初学者，谷歌搜索会帮助你。

对于你的问题，试试这个。

SELECT 
          (select CONCAT(product_id, '-', cost) from  productlist group by product_id order by cost DESC limit 1) as MAX,
          (select CONCAT(product_id, '-', cost) from  productlist group by product_id order by cost ASC limit 1) as MIN,
          (select avg(cost) from  productlist) as AVG
FROM 
           productlist limit 1

Answer 4

这准确地回答了您的问题，但应该注意的是，需要3次表格扫描才能找到这些数据。此外，问题中的示例表明平均值为truncated，从2093.67降至2093。用round替换它可能更好。

SQL Fiddle

SELECT concat('Min ', product_id) 
  FROM productlist
 WHERE cost = (SELECT min(cost) from productlist)
UNION ALL
SELECT concat('Max ', product_id) 
  FROM productlist
 WHERE cost = (SELECT max(cost) from productlist)
UNION ALL
SELECT concat('Avg ', truncate(avg(cost), 0)) 
  FROM productlist

Answer 5

您想要的输出不是您编写的查询你需要尝试这个来获得所需的输出

select 'Min', product_id 
from productlist
where cost = (select min(cost) from productlist)
UNION 
select 'Max', product_id
from productlist
where cost = (select MAX(cost) from productlist)
UNION 
select 'Avg', floor(AVG(cost)) as Avg
from productlist

在mysql查询中使用min，max和avg

5 个答案: