假设我有一个带流派的电影数据库,我想展示除了某些特定类型的所有电影。我已经建立了协会,工作得很好。
为了做到这一点,我遇到了名为Squeel的宝石,并写了这段代码
movies = Movie.joins(:movie_genres).approved
# This is just an array of id's
included_genres = params[:genres][:included_genres]
excluded_genres = params[:genres][:excluded_genres]
if included_genres
# This works just fine
movies = movies.where(movie_genres: {genre_id: included_genres})
# This works too but IMO MySQL IN operator is faster.
#movies = movies.where{movie_genres.genre_id.eq_any included_genres}
end
if excluded_genres
# Here is where the problems occurs, it generates perfectly nice SQL
# but for some reason it doesn't work as expected.
movies = movies.where{movie_genres.genre_id.not_eq_any excluded_genres}
# If we do it this way, it will only not match those movies
# that have all the selected genres at once, i need to match
# all movies that have atleast one of the inputted genres
#movies = movies.where("genre_id NOT IN (?)", excluded_genres)
#movies = movies.where{movie_genres.genre_id.not_eq_all excluded_genres}
end
movies = movies.group(:id)
所以是的,感谢Squeel,我们得到了这个SQL:
SELECT `movies`.* FROM `movies`
INNER JOIN `movie_genres` ON `movie_genres`.`movie_id` = `movies`.`id`
WHERE ((`movie_genres`.`genre_id` != 10 OR `movie_genres`.`genre_id` != 12))
GROUP BY `movies`.`id`;
没有包含类型,因为它们按预期工作。
所以在结果中,where条件看起来甚至都不适用,因为我看到它与否都没有区别。
查看截图:
有没有人有任何想法,为什么它不起作用,我应该从哪里开始挖掘?
非常感谢所有帮助。
答案 0 :(得分:1)
问题在于逻辑,而不是sql。使用“OR”逻辑,您希望线条满足任何条件,因此对于您的查询,您将获得ID为10的行,因为10!= 12.使用WHERE IN - 精细方式
答案 1 :(得分:0)
使用命名范围
解决了这个问题scope :excluding_genres,
lambda { |genres| {
:conditions =>
['movies.id NOT IN
(SELECT movies.id FROM movies
LEFT JOIN movie_genres ON movies.id = movie_genres.movie_id
WHERE movie_genres.genre_id IN (?))', genres]
}}