Question

我有问题。我正在开始使用servlet和Android进行冒险，我设计了一个简单的servlet来编写“Hello world”。现在我想在我的Android应用中收到此消息。我的代码：

public class MyServlet extends Activity implements OnClickListener{

Button button;
TextView outputText;

public static final String URL = "http://10.0.2.2:8080/ServletExample/HelloServletExample";


@Override
public void onCreate(Bundle savedInstanceState) {

    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    findViewsById();

    button.setOnClickListener(this);

}

private void findViewsById() {
    button = (Button) findViewById(R.id.button);
    outputText = (TextView) findViewById(R.id.outputTxt);
}

public void onClick(View view) {

    String output = null;



        HttpClient httpclient = new DefaultHttpClient();
        try {
            HttpResponse response = httpclient.execute(new HttpGet(URL));
            HttpEntity httpEntity = response.getEntity();
            output = EntityUtils.toString(httpEntity);
        } catch (ClientProtocolException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }


    //} catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
    //} catch (IOException e) {
        // TODO Auto-generated catch block
    //}



    outputText.setText(output);


}

我的servlet：

@WebServlet("/HelloServletExample")
public class HelloServletExample extends HttpServlet {
private static final long serialVersionUID = 1L;

/**
 * @see HttpServlet#HttpServlet()
 */
public HelloServletExample() {
    super();
    // TODO Auto-generated constructor stub
}

/**
 * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
 */
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

    PrintWriter out = response.getWriter();
    out.println("Hello World");

}

}

我不知道为什么但我的应用程序崩溃了。我试着评论一些行，结果发现问题是这一行：

HttpEntity httpEntity = response.getEntity();

为什么？

Answer 1

如果您使用 API级别＆gt; = 9 ，则无需使用AsyncTask从Ui线程发出网络请求，只需在Activity onCreate方法中添加StrictMode.ThreadPolicy：

StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().
                                                   permitAll().build();

StrictMode.setThreadPolicy(policy);

Android应用程序停止工作 - servlets和Httpget

1 个答案: