我有一张像下面这样的表
CREATE TABLE Statistics(Stat_Id INT NOT NULL PRIMARY KEY AUTO_INCREMENT,
Period VARCHAR(55),
Location VARCHAR(255),
Rate_per_SqFt INT)
表中的数据是
INSERT INTO Statistics(Period, Location, Rate_per_SqFt)
VALUES('June', 'Location A', 2500),
('June', 'Location B', 2740),
('June', 'Location C', 3200),
('July', 'Location A', 2650),
('July', 'Location B', 2800),
('July', 'Location C', 3250),
('August', 'Location A', 2750),
('August', 'Location B', 2950),
('August', 'Location C', 3230),
('October', 'Location A', 2950),
('October', 'Location B', 3950),
('October', 'Location C', 3530);
我希望输出中的特定月份的行显示为单独的列
Period Location A Location B Location C
June 2500 2740 3200
July 2650 2800 3250
August 2750 2950 3230
October 2950 3950 3530
如何使用查询
执行此操作答案 0 :(得分:4)
SELECT Period,
MAX(CASE WHEN Location = 'Location A' THEN Rate_per_SqFt ELSE NULL END) `Location A`,
MAX(CASE WHEN Location = 'Location B' THEN Rate_per_SqFt ELSE NULL END) `Location B`,
MAX(CASE WHEN Location = 'Location C' THEN Rate_per_SqFt ELSE NULL END) `Location C`
FROM statistics
GROUP BY Period
如果您有未知位置数,则首选
SET @sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'MAX(CASE WHEN Location = ''',
Location,
''' then Rate_per_SqFt ELSE NULL end) AS ',
CONCAT('`',Location,'`')
)
) INTO @sql
FROM statistics;
SET @sql = CONCAT('SELECT Period, ', @sql, '
FROM Statistics
GROUP BY Period');
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
答案 1 :(得分:1)
您可以在此处看到 5种方法到将行转换为列(您提出的问题的摘要形式):methods link