我在哪里可以找到函数argp_parse的源代码?

时间:2012-12-29 07:04:44

标签: linux

我需要功能的GNU Linux代码

    error_t argp_parse(const struct argp *__restrict __argp,int,char **__restrict,unsigned     __flags,int * __arg_index,void *__restrict input)

如果有人知道去哪或有,请发给我。 非常感谢!!

1 个答案:

答案 0 :(得分:2)

glibc的一部分,很容易找到gnu.org上的链接:

来自http://sourceware.org/git/?p=glibc.git;a=blob_plain;f=argp/argp-parse.c;hb=e07bb02a4f9e7d98f79f428a661c5b982286869d

/* Parse the options strings in ARGC & ARGV according to the argp in ARGP.
   FLAGS is one of the ARGP_ flags above.  If END_INDEX is non-NULL, the
   index in ARGV of the first unparsed option is returned in it.  If an
   unknown option is present, EINVAL is returned; if some parser routine
   returned a non-zero value, it is returned; otherwise 0 is returned.  */
error_t
__argp_parse (const struct argp *argp, int argc, char **argv, unsigned flags,
      int *end_index, void *input)
{
  error_t err;
  struct parser parser;
…