Android sqlite无法识别的令牌异常

时间:2012-12-29 06:00:00

标签: android android-sqlite

我试图从sqlite table中获取我的android代码中的一些数据。我收到一个无法识别的令牌异常。请帮助。 这是我的代码的相关部分:

private static final String APPS_CREATE =
        "create table applist (" +
                    "_id integer primary key, " +
                    "deviceid int(10) not null," +
                    "catid int(10)," +
                         ............



private static final String APPCNT_CREATE =
            "create table appcntlist (" +
                    "_id integer primary key, "+
                    "appcntid int , " +
                    "cntappid int);";
    .........................

      public Cursor fetchCntNotes(String cnt){

        Cursor appfinlist=null;

        Cursor temp=mDb.query(CNT_TABLE, new String[]{KEY_ROWID}, KEY_CNTNM + "=\"" + cnt + "\"", null, null , null, null);
        Cursor applist;

        if(temp.moveToFirst()){
            id=temp.getInt(temp.getColumnIndexOrThrow(DbAdapter.KEY_ROWID));
            Log.d("amit","countryname id: "+ id);

            applist=mDb.rawQuery("SELECT appcntid FROM appcntlist WHERE cntappid = "+id, null);
            if(applist.moveToFirst()){
                int[] cntin=new int[applist.getCount()];
                for(int i=0;i<applist.getCount();i++){
                    Log.d("amit","countryname id appid: " + applist.getInt(applist.getColumnIndexOrThrow(DbAdapter.KEY_APPCNTID)));
                    cntin[i]=applist.getInt(applist.getColumnIndexOrThrow(DbAdapter.KEY_APPCNTID));
                    Log.d("amit","countryname id cnt var: " + cntin[i]);
                    applist.moveToNext();   
                }
                appfinlist = mDb.rawQuery("SELECT * FROM applist WHERE _id IN "+cntin+")", null);
                return appfinlist;
            }

这是logcat的相关部分

E / AndroidRuntime(6447):引起:android.database.sqlite.SQLiteException:无法识别的令牌:“[I @ 406488d0]”:,同时编译:SELECT * FROM applist WHERE _id IN [I @ 406488d0]

2 个答案:

答案 0 :(得分:0)

删除cntin并重试我认为查询无效,查询字符串末尾附加了变量。

答案 1 :(得分:0)

我使用了此链接中提出的方法。查看接受答案给出的解决方案 IN clause and placeholders