Question

我正在制作一个简单的游戏程序，但是在游戏开始时遇到了麻烦。我设置了三个功能：开始，游戏，结束。问题是，一旦程序创建了函数，它就会终止，因为没有重新启动来再次通过这些函数。

这是最后一个函数，gameEnd：

def gameEnd ( ):
       print ('Would you like to play again? Y/N.')
       playAgain = ''     **part of the problem is here; the computer reads playAgain as **
       input (playAgain)    **''. Because playAgain is not equal to Y or y, the program **
       if playAgain == 'Y' or 'y':   **exits without ever starting. I need to move **
           gameCore                  **playAgain somewhere logical.**

       else:
          print ('You won Caves of Doom, Caves of Delight ' + wins + ' times.')
          print ('You lost Caves of Doom, Caves of Delight ' + losses + ' times.')
          if wins > losses:
              print ('Good for you. You have a winning record!')

       elif wins == losses:
              print ('Well, you did okay; neither good nor bad.')

       elif wins < losses:
              print ('Tough luck. You have a losing record.')
              time.sleep (1) 
              print ('Farewell, ' + name + ',' + ' and may we meet again sometime soon.')

Answer 1

通过查看代码，我认为您使用的是Python 3.如果您使用的是Python 2，那么请使用raw_input()代替input()。

你的错误是你定义变量的时候。如果您从用户那里获取输入，则编写变量，然后将等号放入符号，然后写入raw_input()或input()。你就是这样做的：

variable = input() #In python 3
variable = raw_input() #In python 2

所以试试这段代码：

def gameEnd():
    print('Would you like to play again? Y/N.')
    playAgain = input("> ")
    if playAgain == 'Y' or playAgain == 'y':
        gameCore()

    else:
        print('You won Caves of Doom, Caves of Delight ' + wins + ' times.')
        print('You lost Caves of Doom, Caves of Delight ' + losses + ' times.')
        if wins > losses:
            print('Good for you. You have a winning record!')

        elif wins == losses:
            print('Well, you did okay; neither good nor bad.')

        elif wins < losses:
            print('Tough luck. You have a losing record.')
            time.sleep(1) 
            print('Farewell, ' + name + ',' + ' and may we meet again sometime soon.')

#End of code

Answer 2

在gameEnd（）上试用此版本。如果用户输入“Y”/“y”以外的任何内容，则退出。

def gameEnd ( ):
    playAgain = raw_input ('Would you like to play again?')

    if playAgain == 'Y' or playAgain == 'y':
        gameCore()

    else:
        print ('You won Caves of Doom, Caves of Delight ' + wins + ' times.')
        print ('You lost Caves of Doom, Caves of Delight ' + losses + ' times.')

    if wins > losses:
        print ('Good for you. You have a winning record!')
    elif wins == losses:
        print ('Well, you did okay; neither good nor bad.')

    elif wins < losses:
        print ('Tough luck. You have a losing record.')
        time.sleep (1)
        print ('Farewell, ' + name + ',' + ' and may we meet again sometime soon.')

Answer 3

此处的输入功能被滥用。使用'input'时，Python解释器会尝试评估输入内容。这就是使用raw_input发回字符串更安全的原因。您可以使用以下代码调整代码的开头：

def gameEnd():
    playAgain = raw_input('Play again ? (Y/y)')
    if any([playInput == 'Y', playInput == 'y']):
       gameCore()

变量值导致程序过早退出

3 个答案: