我目前正在尝试开发一个短信应用程序,并允许用户向多人发送短信。
由于SMS很长,我必须使用位于
之下的sendMultipartTextMessageprivate void sendSMS(final String phoneNumber, String message) {
String SENT = "SMS_SENT";
String DELIVERED = "SMS_DELIVERED";
SmsManager sms = SmsManager.getDefault();
ArrayList<String> parts = sms.divideMessage(message);
int messageCount = parts.size();
Log.i("Message Count", "Message Count: " + messageCount);
ArrayList<PendingIntent> deliveryIntents = new ArrayList<PendingIntent>();
ArrayList<PendingIntent> sentIntents = new ArrayList<PendingIntent>();
PendingIntent sentPI = PendingIntent.getBroadcast(this, 0, new Intent(SENT), 0);
PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0, new Intent(DELIVERED), 0);
for (int j = 0; j < messageCount; j++) {
sentIntents.add(sentPI);
deliveryIntents.add(deliveredPI);
}
// ---when the SMS has been sent---
registerReceiver(new BroadcastReceiver() {
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode()) {
case Activity.RESULT_OK:
Toast.makeText(getBaseContext(), "SMS sent",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
Toast.makeText(getBaseContext(), "Generic failure",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_NO_SERVICE:
Toast.makeText(getBaseContext(), "No service",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_NULL_PDU:
Toast.makeText(getBaseContext(), "Null PDU",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_RADIO_OFF:
Toast.makeText(getBaseContext(), "Radio off",
Toast.LENGTH_SHORT).show();
break;
}
}
}, new IntentFilter(SENT));
// ---when the SMS has been delivered---
registerReceiver(new BroadcastReceiver() {
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode()) {
case Activity.RESULT_OK:
Toast.makeText(getBaseContext(), "SMS delivered",
Toast.LENGTH_SHORT).show();
break;
case Activity.RESULT_CANCELED:
Toast.makeText(getBaseContext(), "SMS not delivered",
Toast.LENGTH_SHORT).show();
break;
}
}
}, new IntentFilter(DELIVERED));
sms.sendMultipartTextMessage(phoneNumber, null, parts, sentIntents, deliveryIntents);
}
当我尝试在这样的循环中将其发送给多个人时,我将遇到一般错误,并且不会发送消息。我怀疑这是因为消息可能是3-4个部分,即使延迟3000毫秒,android系统也无法及时发送消息。
for (int t = 0; t < array.length; t++) {
System.out.println("temp: " + array[t].toString());
try {
sendSMS(array[t].toString(), message);
Thread.sleep(3000);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
编辑:上面的代码在AsyncTask中,它在服务中执行。
答案 0 :(得分:20)
IHMO你没有使用正确的方法。我正在使用另一个,它正在工作。我试着解释一下:
你应该为所有挂起的意图保留一个计数器,因为如果你发送的短信有两个部分,你将收到两个RESULT_OK(或RESULT_ERROR_ *),并且只有当你收到所有部分的结果时,你应该继续发送下一个短信。我不喜欢阻止线程的想法......也许这就是你得到奇怪错误的原因。
我用我的方法重构了你的代码:
private int mMessageSentParts;
private int mMessageSentTotalParts;
private int mMessageSentCount;
private void startSendMessages(){
registerBroadCastReceivers();
mMessageSentCount = 0;
sendSMS(array[mMessageSentCount].toString(), message);
}
private void sendNextMessage(){
if(thereAreSmsToSend()){
sendSMS(array[mMessageSentCount].toString(), message);
}else{
Toast.makeText(getBaseContext(), "All SMS have been sent",
Toast.LENGTH_SHORT).show();
}
}
private boolean thereAreSmsToSend(){
return mMessageSentCount < array.length;
}
private void sendSMS(final String phoneNumber, String message) {
String SENT = "SMS_SENT";
String DELIVERED = "SMS_DELIVERED";
SmsManager sms = SmsManager.getDefault();
ArrayList<String> parts = sms.divideMessage(message);
mMessageSentTotalParts = parts.size();
Log.i("Message Count", "Message Count: " + mMessageSentTotalParts);
ArrayList<PendingIntent> deliveryIntents = new ArrayList<PendingIntent>();
ArrayList<PendingIntent> sentIntents = new ArrayList<PendingIntent>();
PendingIntent sentPI = PendingIntent.getBroadcast(this, 0, new Intent(SENT), 0);
PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0, new Intent(DELIVERED), 0);
for (int j = 0; j < mMessageSentTotalParts; j++) {
sentIntents.add(sentPI);
deliveryIntents.add(deliveredPI);
}
mMessageSentParts = 0;
sms.sendMultipartTextMessage(phoneNumber, null, parts, sentIntents, deliveryIntents);
}
private void registerBroadCastReceivers(){
registerReceiver(new BroadcastReceiver() {
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode()) {
case Activity.RESULT_OK:
mMessageSentParts++;
if ( mMessageSentParts == mMessageSentTotalParts ) {
mMessageSentCount++;
sendNextMessage();
}
Toast.makeText(getBaseContext(), "SMS sent",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
Toast.makeText(getBaseContext(), "Generic failure",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_NO_SERVICE:
Toast.makeText(getBaseContext(), "No service",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_NULL_PDU:
Toast.makeText(getBaseContext(), "Null PDU",
Toast.LENGTH_SHORT).show();
break;
case SmsManager.RESULT_ERROR_RADIO_OFF:
Toast.makeText(getBaseContext(), "Radio off",
Toast.LENGTH_SHORT).show();
break;
}
}
}, new IntentFilter(SENT));
registerReceiver(new BroadcastReceiver() {
@Override
public void onReceive(Context arg0, Intent arg1) {
switch (getResultCode()) {
case Activity.RESULT_OK:
Toast.makeText(getBaseContext(), "SMS delivered",
Toast.LENGTH_SHORT).show();
break;
case Activity.RESULT_CANCELED:
Toast.makeText(getBaseContext(), "SMS not delivered",
Toast.LENGTH_SHORT).show();
break;
}
}
}, new IntentFilter(DELIVERED));
}
答案 1 :(得分:2)
我遇到了同样的错误“通用故障”发生时使用此代码。但我使用数组[mMessageSentCount] .toString()。trim()。 然后它解决了我的问题&amp;它的工作正常。 感谢