Question

我有一个多播委托，我正在调用两个方法。如果第一个方法中存在异常并处理它，如何继续第二个方法调用？我附上下面的代码。在下面的代码中，第一个方法抛出异常。但我想知道如何通过多播委托调用继续执行第二种方法。

public delegate void TheMulticastDelegate(int x,int y);
    class Program
    {
            private static void MultiCastDelMethod(int x, int y)
            {
                    try
                    {
                            int zero = 0;
                            int z = (x / y) / zero; 
                    }
                    catch (Exception ex)
                    {                               
                            throw ex;
                    }
            }

            private static void MultiCastDelMethod2(int x, int y)
            {
                    try
                    {
                            int z = x / y;
                            Console.WriteLine(z);
                    }
                    catch (Exception ex)
                    {
                            throw ex;
                    }
            }
            public static void Main(string[] args)
            {
                    TheMulticastDelegate multiCastDelegate = new TheMulticastDelegate(MultiCastDelMethod);
                    TheMulticastDelegate multiCastDelegate2 = new TheMulticastDelegate(MultiCastDelMethod2);

                    try
                    {
                            TheMulticastDelegate addition = multiCastDelegate + multiCastDelegate2;

                            foreach (TheMulticastDelegate multiCastDel in addition.GetInvocationList())
                            {
                                    multiCastDel(20, 30);
                            }
                    }
                    catch (Exception ex)
                    {
                            Console.WriteLine(ex.Message);
                    }

                    Console.ReadLine();
            }
    }

Answer 1

在循环中移动try..catch：

foreach (TheMulticastDelegate multiCastDel in addition.GetInvocationList())
{
    try
    {
        multiCastDel(20, 30);
    }
    catch (Exception ex)
    {
        Console.WriteLine(ex.Message);
    }
}

此外，您将throw ex;替换为throw ;，因为前者会创建一个新的异常，这是不必要的。它应该看起来像：

private static void MultiCastDelMethod(int x, int y)
{
    try
    {
        int zero = 0;
        int z = (x / y) / zero;
    }
    catch (Exception ex)
    {
        throw ;
    }
}

多播委托中的异常处理

1 个答案: