Question

我几天来一直坚持这个问题。这是我的第一个Rails应用程序，而且我差不多完成了，只是因此而显着减慢了。

我读到使用accepts_nested_attributes_for是我在配方中嵌入配料以便与表格一起使用的问题的最佳解决方案，但到目前为止我没有运气。我已经阅读了关于这个主题的所有内容。 API说模型现在有一个（在我的情况下）ingredients_attributes =方法，我还没有看到。我尝试在控制台中使用带有哈希

的update_attributes

recipe.update_attrubutes {:ingredients_attributes=>[{:name=>"Test Ingredient"}]}

返回 true ，但在配方对象中没有显示任何变化。

我尝试了很多方法，我的第一个方法就是在我的View里面的forms_for中使用fields_for。由于这不起作用，我测试代码无济于事，我开始深入研究，问题肯定比View更深入。

非常感谢任何帮助。我的代码如下

食谱模型

对于db风格的名称和显示样式名称之间令人困惑的转换感到抱歉。到目前为止，这是我最好的解决方法，以维护它们。

class Recipe < ActiveRecord::Base

  DISH_TYPES={""=>"", "Breakfast"=>"breakfast", "Lunch"=>"lunch", "Soup"=>"soup", "Entree"=>"entree", "Desert"=>"desert"}
  SEASONS={"Any Season"=>"any", "Fall"=>"fall", "Winter"=>"winter", "Spring"=>"spring", "Summer"=>"summer"}
  DIETS={""=>"", "Vegan"=>"vegan", "Vegetarian"=>"vegetarian", "Omnivore"=>"omnivore"}

  DISH_TYPES_R={""=>"", "breakfast"=>"Breakfast", "lunch"=>"Lunch", "soup"=>"Soup", "entree"=>"Entree", "desert"=>"Desert"}
  SEASONS_R={"any"=>"Any Season", "fall"=>"Fall", "winter"=>"Winter", "spring"=>"Spring", "summer"=>"Summer"}
  DIETS_R={""=>"", "vegan"=>"Vegan", "vegetarian"=>"Vegetarian", "omnivore"=>"Omnivore"}

  attr_protected :user_id
  # Do NOT include user_id in the attr_accessible method, to avoid
  # the possibility of it being changed externally.
  belongs_to :user
  validates_presence_of :user  
  has_many :ingredients, dependent: :destroy # , inverse_of: :recipe

  # Allows for forms to write attributes down the hierarchy.
  accepts_nested_attributes_for :ingredients, allow_destroy: true , reject_if: lambda { |a| a[:content].blank? }

  before_save do
    # Lowercase and convert to strings all of the attributes
    # that require a specific format, namely the values in the
    # constant hashes above.
    STRING_ATTRIBUTES.each do |s|
      self.send("#{s}=".to_sym, self.send(s).downcase.to_s)
    end
  end

  validates :user_id, presence: true
  validates :name,  presence: true,
                    length: { maximum: 64 } #,uniqueness: true
  validates :dish_type, inclusion: { in: DISH_TYPES.values }
  validates :season, inclusion: { in: SEASONS.values }
  validates :diet, inclusion: { in: DIETS.values}
  validates :directions,  presence: true,
                          length: { maximum: 8192 }

  validates_associated :ingredients


  default_scope order: "recipes.created_at DESC"


  def method_missing (method)
    method = method.to_s
    if method.slice!("display_")
      if STRING_ATTRIBUTES.include?(method.to_sym)
        hash_name = method.upcase + 'S_R'
        Recipe.const_get(hash_name)[self.send(method.to_sym)]
      else
        method
      end
    else 
      method.class
    end
  end

  private

    STRING_ATTRIBUTES = [:dish_type, :season, :diet]

end

成分模型

class Ingredient < ActiveRecord::Base

  attr_protected :id, :recipe_id
  belongs_to :recipe

  validates_presence_of :name
  #validates_presence_of :recipe
end

配方控制器

我读过我不应该在控制器中更改任何内容。我只添加了一行，以便在我的视图中显示成分表单

class RecipesController < ApplicationController
  before_filter :signed_in_user, only: [:create, :edit, :destroy]

  def index
    @recipes = Recipe.all
  end

  def new
    if signed_in?
      @recipe = current_user.recipes.build 
      @recipe.ingredients.build
    else
      flash[:error] = "First you have to register! Sign up here and start adding recipes ASAP."
      redirect_to signup_path
    end
  end

  def create
    @new_recipe = current_user.recipes.build(params[:recipe])
    if @new_recipe.save
      flash[:success] = "You've successfully added #{@new_recipe.name}!"
      redirect_to @new_recipe
    else
      redirect_to 'new'
    end
  end

  def edit
    @recipe = Recipe.find(params[:id])
  end

  def show
    @recipe = Recipe.find(params[:id].to_i)
  end

end

成分控制器

我不相信成分控制器有任何用处，因为成分（现在）只能通过其父配方进行访问。

我会根据要求提供意见，但正如我先前所说，我不相信这是高级别的。

Answer 1

您需要为attr_accessible模型设置Recipe并添加:ingredients_attributes
正如我在您的配置中看到的那样，您对ingrediens_attributes有reject_if: lambda { |a| a[:content].blank? }，而您只使用名称

accepts_nested_attributes_for不保存嵌套属性

食谱模型

成分模型

配方控制器

成分控制器

1 个答案: