Question

我在Oracle中有两个表

TABLE A ( all fields are primary keys)
-----------------------------------------
SID  (INT)   
SDAY  (CHAR) 
DATETIME (DATETIME)

TABLE B ( all fields are primary keys- same as table A)
---------------------------------------------------------
SID
SDAY
DATETIME

我想找到表A中的记录

where A.SID = B.SID
AND A.SDAY = B.SDAY
AND A.DATETIME <> B.DATETIME

（即 - 我想在表A中找到与表B中除日期时间之外的相应列匹配的记录）

直接INNER JOIN SQL没有给我结果。有什么想法吗？

这也无效

SELECT A.* FROM TABLE_A A
WHERE  EXISTS (
SELECT 'X' FROM TABLE_B B
WHERE A.SID = B.SID
AND A.SDAY = B.SDAY 
AND A.DATETIME <> B.DATETIME)

Answer 1

我可能会把它作为一个内部联接而不是一个存在，但我希望你的工作。

SELECT A.* 
FROM TABLE_A A
INNER JOIN TABLE_B B
ON  A.SID = B.SID
AND A.SDAY = B.SDAY 
AND A.DATETIME <> B.DATETIME

如果您仍未获得结果，可以尝试发布一些样本数据供我们测试

您可以运行以完整测试以显示上述联接有效：

CREATE TABLE #Table_a
(
    [SID] INT, 
    SDAY CHAR,
    [DATETIME] DATETIME
)

CREATE TABLE #Table_b
(
    [SID] INT, 
    SDAY CHAR,
    [DATETIME] DATETIME
)

INSERT INTO #Table_a
        ( SID, SDAY, DATETIME )
VALUES  ( 0, -- SID - int
          'A', -- SDAY - char
          '2012-12-27 23:00:01'  -- DATETIME - datetime
          )
INSERT INTO #Table_a
        ( SID, SDAY, DATETIME )
VALUES  ( 2, -- SID - int
          'B', -- SDAY - char
          '2012-12-27 23:00:01'  -- DATETIME - datetime
          )
INSERT INTO #Table_a
        ( SID, SDAY, DATETIME )
VALUES  ( 3, -- SID - int
          'C', -- SDAY - char
          '2012-12-27 23:00:01'  -- DATETIME - datetime
          )




INSERT INTO #Table_B
        ( SID, SDAY, DATETIME )
VALUES  ( 0, -- SID - int
          'A', -- SDAY - char
          '2012-12-27 3:00:01'  -- DATETIME - datetime
          )
INSERT INTO #Table_B
        ( SID, SDAY, DATETIME )
VALUES  ( 2, -- SID - int
          'B', -- SDAY - char
          '2012-12-27 3:00:01'  -- DATETIME - datetime
          )
INSERT INTO #Table_B
        ( SID, SDAY, DATETIME )
VALUES  ( 3, -- SID - int
          'C', -- SDAY - char
          '2012-12-27 23:00:01'  -- DATETIME - datetime
          )


SELECT A.* 
FROM #TABLE_A A
INNER JOIN #TABLE_B B
ON  A.SID = B.SID
AND A.SDAY = B.SDAY 
AND A.DATETIME <> B.DATETIME


DROP TABLE #Table_a
DROP TABLE #Table_b

Answer 2

如果您显示如下表格定义，也许您的问题会更容易阅读：

- 我在Oracle中有两个表

CREATE TABLE TABLE_A -- BTW: why the caps?
  ( SID INTEGER NOT NULL
  , SDAY CHAR NOT NULL
  , ZDATETIME DATETIME NOT NULL -- note: using a typename as an identier
                                -- will break things.
  , PRIMARY KEY (SID,SDAY,ZDATETIME)
  );

CREATE TABLE TABLE_B -- all (1)fields are primary keys
   ( SID SDAY DATETIME NOT NULL PRIMARY KEY
   );

[也许这应该是评论，但评论没有格式化的可能性]

（即 - 我想在表A中找到与表B中相应列相匹配的记录

EXISTS

除日期时间外）

NOT EXISTS

好的，现在解决方案：

SELECT A.* FROM TABLE_A A

WHERE  EXISTS (
    SELECT 1 FROM TABLE_B B
    WHERE A.SID = B.SID
    AND A.SDAY = B.SDAY 
    )
AND NOT  EXISTS (
    SELECT 2 FROM TABLE_B B
    WHERE A.SID = B.SID
    AND A.SDAY = B.SDAY 
    AND A.ZDATETIME = B.ZDATETIME
    )
    ;

SQL - 识别主键不匹配的表中的记录

2 个答案: