我有一个SQL Server 2000数据库,大约有220个表。这些表之间有许多外键关系。通过性能分析,我们发现许多这些外键关系都缺少索引。我不想对性能问题做出反应,而是积极主动地找到所有缺少索引的外键。
如何以编程方式确定哪个外键缺少索引?
答案 0 :(得分:17)
SELECT *
FROM sys.foreign_keys fk
WHERE EXISTS
(
SELECT *
FROM sys.foreign_key_columns fkc
WHERE fkc.constraint_object_id = fk.object_id
AND NOT EXISTS
(
SELECT *
FROM sys.index_columns ic
WHERE ic.object_id = fkc.parent_object_id
AND ic.column_id = fkc.parent_column_id
AND ic.index_column_id = fkc.constraint_column_id
)
)
我没有SQL Server 2000
方便的副本,但您可能需要将sys.foreign_key
更改为sysforeignkeys
等,如here
所述。
此查询选择所有没有索引的外键,该索引覆盖构成密钥的所有列。
这也支持多列外键。
但是,如果存在覆盖所有列的复合索引但是它们不是此索引中最左侧的列,则会返回误报。
例如,如果FOREIGN KEY (col2, col3)
上有(col1, col2, col3)
和索引,则会返回有一个索引,尽管该索引对此外键不可用。
答案 1 :(得分:7)
这是一个适用于由同事创作的SQL Server 2000的答案:
/*
Description:
This script outputs a table with all the current database un-indexed foreign keys.
The table has three columns ( TableName , ColumnName, ForeignKeyName )
TableName: The table containing the un-indexed foreign key
ColumnName: The foreign key column that’s not indexed
ForeignKeyName: Name of foreign key witch column doesn’t have an index
*/
DECLARE
@TableName varchar(255),
@ColumnName varchar(255),
@ForeignKeyName sysname
SET NOCOUNT ON
SET TRANSACTION ISOLATION LEVEL READ UNCOMMITTED
DECLARE FKColumns_cursor CURSOR Fast_Forward FOR
SELECT cu.TABLE_NAME, cu.COLUMN_NAME, cu.CONSTRAINT_NAME
FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS ic
INNER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE cu ON ic.CONSTRAINT_NAME = cu.CONSTRAINT_NAME
WHERE ic.CONSTRAINT_TYPE = 'FOREIGN KEY'
CREATE TABLE #temp1(
TableName varchar(255),
ColumnName varchar(255),
ForeignKeyName sysname
)
OPEN FKColumns_cursor
FETCH NEXT FROM FKColumns_cursor INTO @TableName, @ColumnName, @ForeignKeyName
WHILE @@FETCH_STATUS = 0
BEGIN
IF ( SELECT COUNT(*)
FROM sysobjects o
INNER JOIN sysindexes x ON x.id = o.id
INNER JOIN syscolumns c ON o.id = c.id
INNER JOIN sysindexkeys xk ON c.colid = xk.colid AND o.id = xk.id AND x.indid = xk.indid
WHERE o.type in ('U')
AND xk.keyno <= x.keycnt
AND permissions(o.id, c.name) <> 0
AND (x.status&32) = 0
AND o.name = @TableName
AND c.name = @ColumnName
) = 0
BEGIN
INSERT INTO #temp1 SELECT @TableName, @ColumnName, @ForeignKeyName
END
FETCH NEXT FROM FKColumns_cursor INTO @TableName, @ColumnName, @ForeignKeyName
END
CLOSE FKColumns_cursor
DEALLOCATE FKColumns_cursor
SELECT * FROM #temp1 ORDER BY TableName
答案 2 :(得分:5)
基于上面的代码,删除临时表并获取脚本来创建索引。
/*
Description:
*/
DECLARE
@SchemaName varchar(255),
@TableName varchar(255),
@ColumnName varchar(255),
@ForeignKeyName sysname
SET NOCOUNT ON
SET TRANSACTION ISOLATION LEVEL READ UNCOMMITTED
DECLARE FKColumns_cursor CURSOR Fast_Forward FOR
SELECT cu.TABLE_SCHEMA, cu.TABLE_NAME, cu.COLUMN_NAME, cu.CONSTRAINT_NAME
FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS ic
INNER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE cu ON ic.CONSTRAINT_NAME = cu.CONSTRAINT_NAME
WHERE ic.CONSTRAINT_TYPE = 'FOREIGN KEY'
CREATE TABLE #temp1(
SchemaName varchar(255),
TableName varchar(255),
ColumnName varchar(255),
ForeignKeyName sysname
)
OPEN FKColumns_cursor
FETCH NEXT FROM FKColumns_cursor INTO @SchemaName,@TableName, @ColumnName, @ForeignKeyName
WHILE @@FETCH_STATUS = 0
BEGIN
IF ( SELECT COUNT(*)
FROM sysobjects o
INNER JOIN sysindexes x ON x.id = o.id
INNER JOIN syscolumns c ON o.id = c.id
INNER JOIN sysindexkeys xk ON c.colid = xk.colid AND o.id = xk.id AND x.indid = xk.indid
WHERE o.type in ('U')
AND xk.keyno <= x.keycnt
AND permissions(o.id, c.name) <> 0
AND (x.status&32) = 0
AND o.name = @TableName
AND c.name = @ColumnName
) = 0
BEGIN
INSERT INTO #temp1 SELECT @SchemaName, @TableName, @ColumnName, @ForeignKeyName
END
FETCH NEXT FROM FKColumns_cursor INTO @SchemaName,@TableName, @ColumnName, @ForeignKeyName
END
CLOSE FKColumns_cursor
DEALLOCATE FKColumns_cursor
SELECT 'CREATE INDEX IDX_' + ForeignKeyName + ' ON ' + SchemaName + '.' + TableName + '(' + ColumnName +')'
FROM #temp1
ORDER BY TableName
drop table #temp1
答案 3 :(得分:1)
在我的帖子"SQL Script to create indexes for Foreign keys"中,我添加了2个实现的链接:paul_nielsen和tklimczak's (login to sqlservercentral是必需的)
答案 4 :(得分:0)
首先:列出具有外键约束的列。这将有所帮助:
Query to get all foreign key constraints in SQL Server 2000
与sysindexes
和syscolumns
表交叉比较; keys
中的sysindexes
字段包含索引中所有键的列表。
答案 5 :(得分:0)
注意:这是针对SQL Server 2005+的,但这是我发现的关于此主题的唯一问题。
--Finds foreign keys without indexes
--How to interpret:
--When we delete frpm PkTable, it checks FkColumn for the PkId we are deleting.
--So if FkTable doesn't have an index on FkColumn, then we cannot delete a row from PkTable because it is too slow.
SELECT rt.name as PkTableName, rc.name as PkColumnName,
fk.name FkName, t.name as FkTableName, c.name as FkColumnName, ddps.row_count, i.name as IndexName
FROM sys.foreign_key_columns fkc
inner join sys.foreign_keys fk on fkc.constraint_object_id = fk.object_id
inner join sys.tables t on fkc.parent_object_id = t.object_id
inner join sys.columns c on fkc.parent_object_id = c.object_id and fkc.parent_column_id = c.column_id
inner join sys.tables rt on fkc.referenced_object_id = rt.object_id
inner join sys.columns rc on fkc.referenced_object_id = rc.object_id and fkc.referenced_column_id = rc.column_id
inner join sys.indexes ri on t.object_id = ri.object_id
inner JOIN sys.dm_db_partition_stats AS ddps ON ri.OBJECT_ID = ddps.OBJECT_ID AND ri.index_id = ddps.index_id
left join sys.index_columns ic on ic.object_id = t.object_id and ic.column_id = c.column_id
left join sys.indexes i on ic.object_id = i.object_id and i.index_id = ic.index_id
where ri.index_id < 2 and i.index_id is null and ddps.row_count > 0
order by
--PkTableName,
ddps.row_count desc