Question

我正在尝试解析一个字符串，但我得到的回复是不正确的，我试图从doc =中提取问号？和slide =？，但我得到了

doc id：＆amp; doc = 9729＆amp; slide = 214679＆amp; #doc = 9729＆amp; slide = 21

幻灯片ID：＆amp; slide = 214679＆amp; #doc = 9729

string：

HTTP：/securefinder.com/ajax_query/delimiter.aspx Q = LNG＆安培; F = 1.1＆安培; DOC = 9729＆安培;滑动= 214679＆安培;＃DOC = 9729＆安培;滑动= 214679＆安培;

似乎它不接受＆amp;作为划界人物。

 <?php

    function from_to($string, $from, $to) {
        //Calculate where each substring is found inside of $string
        $pos_from = strpos($string, $from);
        $pos_to   = strpos($string, $to);


        //The function will break if $to appears before $from, throw an exception.
        if ($pos_from > $pos_to) {

        }

        return substr(
            $string,
            $pos_from, //From where the $from starts (first character of $from)
            $pos_to - $pos_from + strlen($to) //To where the $to ends. (last character of $to)
        );
    }

    $str = "http:/securefinder.com/ajax_query/delimiter.aspx?q=LNG&f=1.1&doc=9729&slide=214679&#doc=9729&slide=214679&";


         $doc_id = from_to($str, 'doc=', '&');
          $slide_id = from_to($str, 'slide=', '&');


echo 'doc id:' . $doc_id ;
echo 'slide id:'. $slide_id;



    ?>

Answer 1

考虑使用prase_url()分解网址，然后在查询结果上使用parse_str()首先按#分解您的查询，&的结果，最后是=的结果。

这样您就不需要编写自己的解析逻辑了。从这里你将获得一个很好的数组来操纵，而不是试图弄清楚如何操纵你的字符串。

Answer 2

尝试使用 preg_match

$str = "http:/securefinder.com/ajax_query/delimiter.aspx?q=LNG&f=1.1&doc=9729&slide=214679&#doc=9729&slide=214679&";

preg_match("/doc=(.*?)&/i", $str, $d);    
preg_match("/slide=(.*?)&/i", $str, $s);

$doc_id   =  $d[1];
$slide_id =  $s[1];

echo 'doc id:' . $doc_id ;
echo 'slide id:'. $slide_id;

php strpos忽略了角色

2 个答案: