Question

从此Array()我想获取amount_total，运费和合作伙伴的价值，并由特定合作伙伴对其进行总计。例如，partner=>2665应该有一个41.79 + 55.95的amount_total，依此类推，请帮忙。我不想通过SQL来实现，因为我也需要数据。

Array
(
    [0] => Array
    (
        [amount_total] => 41.79
        [amount_shipping] => 4.99
        [amount_partner] => 14.8
        [partner] => 2665
    )
    [1] => Array
    (
        [amount_total] => 55.95
        [amount_shipping] => 19.96
        [amount_partner] => 11
        [partner] => 2665
    )
    [2] => Array
    (
        [amount_total] => 51.96
        [amount_shipping] => 7.98
        [amount_partner] => 23.98
        [partner] => 51754
    )
    [3] => Array
    (
        [amount_total] => 24.55
        [amount_shipping] => 4.99
        [amount_partner] => 5.67
        [partner] => 11513
    )
)

Answer 1

您可以使用PHP来实现此目的，但这不是必需的。数据库可以更有效地完成这项工作

我假设您当前的查询看起来像这样

SELECT
    `amount_total`,
    `amount_shipping`,
    `amount_partner`,
    `partner`
FROM
    `salesLeads`
WHERE
    [..]

MySQL为您提供了很好的聚合函数，例如SUM可以与GROUP BY

一起使用

SELECT
    SUM( `amount_total` ) AS `amount_total`,
    SUM( `amount_shipping` ) AS `amount_shipping`,
    SUM( `amount_partner` ) AS `amount_partner`.
    `partner`
FROM 
    `salesLeads`
WHERE
     [..]
GROUP BY
     `partner`

在您的PHP脚本中，您可以通过相同的方式访问它，但它具有已由合作伙伴分组和汇总的最终数字

e.g。

if ($result = $mysqli->query($query)) {

    while ($row = $result->fetch_assoc()) {
        print_r( $row );
    }

    $result->close();
}

修改

因为你想要一个PHP解决方案，它再次比查询两次更有效：

$partnerSums = array(); while ( $row = $result->fetch_assoc() ) { if ( !array_key_exists( $row['partner'], $partnerSums ) { $partnerSums[$row['partner']] = $row; } else { $partnerSums[$row['partner']]['amount_total'] += $row['amount_total']; $partnerSums[$row['partner']]['amount_shipping'] += $row['amount_shipping']; $partnerSums[$row['partner']]['amount_partner'] += $row['amount_partner']; } } print_r( $partnerSums );

Answer 2

我认为循环遍历此数组并将总数存储在新数组中，同时检查in_array（more here）就足够了。你需要做的就是每次循环一个元素，检查它是否已经在新数组中，如果是 - 执行必要的数学运算

Answer 3

我会建议这样的事情：

   $res['totals']=array();

foreach($result as $res)
{
    $partner = $result['partner'];
    $res['totals'][$partner]+=$result['total_amount'];
}

通过这种方式，您可以在一个位置获得所需的所有数据：合作伙伴数组＆＃39; $ res＆＃39;。

希望它对你有所帮助。

从数组和总和中获取唯一值

3 个答案: