Question

我有一个mysql表T1，它由两列INT组成，它们将car_id链接到part_id。单个car_id可以具有多个part_id，并且相同的part_id可以对应于多个car_id。例如，

car_id   part_id
  1        1  
  1        2  
  1        8  
  2        3  
  3        4  
  4        2  
  4        6  
     ...  
  10       1  
  10       2  
     ...  
  20       1  
  20       2  
  20       8

要获取与car_id = 1关联的所有part_ids，我运行查询

SELECT car_id, part_id FROM T1 WHERE car_id=1

并得到结果：

car_id   part_id
  1        1  
  1        2  
  1        8

现在，我想找到至少包含与car_id = 1相关联的part_ids（例如＆gt; = 2/3）的所有剩余car_id。（在这个例子中，我应该得到所有car_ids至少有2个part_id 1,2和8，如我的SELECT查询后所示。所以，我应该得到car_ids 1,10和20）。

我可以使用：

找到包含所有part_ids 1,2和8的car_ids

SELECT car_id, part_id 
      FROM T1 
      WHERE part_id = ALL (SELECT part_id FROM T1 WHERE car_id=1). The result is car_ids 1 and 20.

我可以使用：

找到包含任何值1,2和8的car_ids

SELECT car_id, part_id 
       FROM T1 
       WHERE part_id = ANY (SELECT part_id FROM T1 WHERE car_id=1). The result is car_ids 1,4,10 and 20.

如何在ANY和ALL之间指定一些数字？

Answer 1

要获得包含2个或更多汽车car_id的{{1}}的所有1个

part_id

Answer 2

这是一种方式：

select car_id
from (select cp.car_id,
             sum(case when cp.part_id is not null and cp1.part_id is not null then 1 else 0 end) as PartsInCommon,
             sum(case when cp.part_id is not null and cp1.part_id is null then 1 else 0 end) as ThisCarOnly,
             sum(case when cp.part_id is null and cp1.part_id is not null then 1 else 0 end) as ThatCarOnly
      from CarParts cp full outer join
           (select part_id
            from CarParts cp
            where car_id = 1
           ) cp1
           on cp.part_id = cp1.part_id
      group by cp.car_id
     ) t
where PartsInCommon / (PartsInCommon + ThisCarOnly + ThatCarOnly) >= 2.0/3

此查询计算两辆车或两辆车共用的零件数量。然后where子句定义特定条件。

如果你想要部分列表，那么Juergen对group_concat()有正确的想法，尽管你没有在问题中指明这一点。

Answer 3

尝试此查询。我尽可能多地尝试

SELECT 
    car_id,
    GROUP_CONCAT(part_id)
FROM cars
WHERE FIND_IN_SET
    (part_id ,(SELECT GROUP_CONCAT(part_id) FROM cars WHERE car_id = 1)) 
GROUP BY car_id
HAVING COUNT(part_id) >= 2

这是sqlfiddle演示http://sqlfiddle.com/#!2/8e563/17

MySQL在ANY和ALL之间进行选择

3 个答案: