Question

CREATE TABLE one_many
  (name VARCHAR2(20),
  acc_num VARCHAR2(20))

  INSERT ALL 
  INTO one_many VALUES ('abc','a-110')
  INTO one_many VALUES ('def','b-256')
  INTO one_many VALUES ('xyz','v-586')
  INTO one_many VALUES ('uij','o-451')
  INTO one_many VALUES ('pqr','')
  INTO one_many VALUES ('abc','a-120')
  INTO one_many VALUES ('xyz','v-588')
  SELECT * FROM dual;

如何找到一个多个案例，即选择那些具有多个acc_num的名称

Desired o/p:
NAME ACC_NUM
abc  a-110  
abc  a-120  
xyz  v-586  
xyz  v-588

Answer 1

在这种情况下，您需要使用GROUP BY和HAVING。

SELECT name, COUNT(*) totalCount
FROM one_many
GROUP BY name
HAVING COUNT(*) > 1

SQLFiddle Demo Link (two queries included)

或

也许这就是你的意思。

SELECT a.*
FROM one_many a
     INNER JOIN
      (
        SELECT name, COUNT(*) totalCount
        FROM one_many
        GROUP BY name
        HAVING COUNT(*) > 1
      ) b ON a.name = b.name

SQLFiddle Demo

Answer 2

此查询似乎是为分析函数设计的：

select name, acc_num
from (select om.*,
             count(*) over (partition by name) as NumOnAccount
      from one_many om
     ) t
where NumOnAccount > 1

Answer 3

你可以这样做吗

      SELECT * FROM one_many
       WHERE acc_num IN 
                     (SELECT acc_num FROM 
                                     one_many
                                      GROUP BY name ,acc_num 
                                       HAVING COUNT(*)>1
                      );

找到有多个帐号的名字

3 个答案: