awk字段分隔符\ [\]

Question

给出以下命令：

cat 11 | awk -F"[\[\]]" '{print $1,$2}'        
cat 11 | awk -F"[\]\[]" '{print $1,$2}'

为什么awk输出不同：

zxscgdb@linux:~/tmp> cat 11    
12-05 09:07:53:33 F[zxinit_lib.c] L[485] E[10106] process:zxsc_gdb is ok.    
12-05 09:08:03:35 F[zxinit_lib.c] L[485] E[10106] process:zxsc_gdb is ok.    
12-05 09:08:13:37 F[zxinit_lib.c] L[485] E[10106] process:zxsc_gdb is ok.

zxscgdb@linux:~/tmp> cat 11 | awk -F"[\]\[]" '{print $1,$2}'    
awk: warning: escape sequence `\]' treated as plain `]'    
awk: warning: escape sequence `\[' treated as plain `['    
12-05 09:07:53:33 F zxinit_lib.c    
12-05 09:08:03:35 F zxinit_lib.c    
12-05 09:08:13:37 F zxinit_lib.c    

zxscgdb@linux:~/tmp> cat 11 | awk -F"[\[\]]" '{print $1,$2}'    
awk: warning: escape sequence `\[' treated as plain `['    
awk: warning: escape sequence `\]' treated as plain `]'    
12-05 09:07:53:33 F[zxinit_lib.c] L[485] E[10106] process:zxsc_gdb is ok.     
12-05 09:08:03:35 F[zxinit_lib.c] L[485] E[10106] process:zxsc_gdb is ok.     
12-05 09:08:13:37 F[zxinit_lib.c] L[485] E[10106] process:zxsc_gdb is ok. 

Answer 1

我的理解是您希望使用[和]作为分隔符。在这种情况下：

awk -F '[][]' '{print $1,$2}' 11

]后的字符[（如[]]中所示）将被视为自身。

Answer 2

您需要使用单引号绕过shell解释：

awk -F'[\\[\\]]' '{print $2,$4}' 11

或逃避第一个退格：

 awk -F"[\\\[\\\]]" '{print $2,$4}' 11