提升文件上传器编译错误

时间:2012-12-25 14:16:31

标签: scala lift

我想用Lift实现图像uplad。从this开始。我是Lift的新手。

我做了一些修改。现在我只想看到一些有用的东西。不一定是图像。到目前为止,我有:

package code 
package snippet 
import net.liftweb.http.S
import net.liftweb.common.Full
import net.liftweb.common.Empty
import net.liftweb.common.Box
import net.liftweb.http.FileParamHolder
import net.liftweb.util._
import Helpers._
import scala.xml.Group
import scala.xml.NodeSeq
import net.liftweb.http.SHtml

class AddEntry {

  // Add a variable to hold the FileParamHolder on submission
  var fileHolder : Box[FileParamHolder] = Empty

  def doTagsAndSubmit (t : String) {

//    val e : Expense = ...
    // Add the optional receipt if it’s the correct type
    val receiptOk = fileHolder match {
      // An empty upload gets reported with a null mime type,
      // so we need to handle this special case
      case Full(FileParamHolder(_, null, _, _)) => true

      case Full(FileParamHolder(_, mime, _, data))
        if mime.startsWith("image/") => {
//          e.receipt(data).receiptMime(mime)
          true
        }

      case Full(_) => {
        S.error("Invalid receipt attachment")
        false
      }

      case _ => true
    }

//    (e.validate, receiptOk) match {
//    }
}

  def addEntry(content: NodeSeq): NodeSeq = {

      bind("prefix", content,
              "receipt" -> SHtml.fileUpload(fileHolder = _)) //compiler error: type mismatch; found : net.liftweb.http.FileParamHolder required: net.liftweb.common.Box[net.liftweb.http.FileParamHolder]
  }
}

html:

<lift:AddEntry.addEntry form="POST" multipart="true">
    <td>Receipt (JPEG or PNG)</td>
<td><prefix:receipt /></td>
</lift:AddEntry.addEntry>

在代码中注释我在"receipt" -> SHtml.fileUpload(fileHolder = _)中遇到编译器错误:错误:类型不匹配;发现:net.liftweb.http.FileParamHolder required:net.liftweb.common.Box [net.liftweb.http.FileParamHolder]

不明白,因为fileHolder的类型为Box[FileParamHolder]。它应该与表达式fileHolder = _相关,但不知道如何。

提前致谢。

1 个答案:

答案 0 :(得分:3)

从API看来,SHtml.fileUpload似乎提供了FileParamHolder,但您的变量fileHolder的类型为Box[FileParamHolder],因此将这两者设置为开箱即用。

如果您尝试这样做:

SHtml.fileUpload(f => fileHolder = Box !! f))

它将为您提供Box[FileParamHolder],并允许您编译代码。