Question

你能告诉我为什么我收到错误为Subscript out of range- ArrParent吗？当我使用MsgBox(Lbound(ArrParent))时 - 它给我1，当我使用MsgBox(Ubound(ArrParent))时 - 它给我960.所以在下面的行中我得到了out of range错误。 Dic(ArrParent(Count))=Count+2查找以下完整代码：

代码

    Sub ParentPIDNumber(ArrParent,ob3,ob2,ob4)

        Dim Dic,DicItems,Dickeys
        Dim Count

        Set Dic = CreateObject("Scripting.Dictionary")

        Count=LBound(ArrParent)
        'MsgBox(ArrParent(Count))
        Do Until Count > UBound(ArrParent) - 1

           Dic(ArrParent(Count))=Count+2 'here Dictionary keys are holding the row numbers as their Items

        Count=Count+1
        Loop

        ParentChildBinding Dic,ob3,ob2,ob4

    End Sub
   Sub FileredOpenProcessToDel(ob3,ob2,ob4)

        Dim ColumnToFilter,TotalRows
        Dim rngFilter,cel,str,rangesToRemove,x 
        Dim strToRemove : strToRemove = ""
        Dim ArrParent

        objExcel1.ScreenUpdating = False
        objExcel1.Calculation = -4135  'xlCalculationManual
        ColumnToFilter=objExcel1.Application.WorksheetFunction.CountA(ob4.Rows(1)) - 1
        ob4.Range(ob4.Cells(1,ColumnToFilter),ob4.Cells(1,ColumnToFilter)).AutoFilter ColumnToFilter, "Open",,,True 

        'Dim rngFilter as Range
        Set rngFilter = objExcel1.Application.Intersect(ob4.UsedRange,ob4.UsedRange.Offset(1),ob4.Columns(1)).SpecialCells(12)'xlCellTypeVisible
           'MsgBox(rngFilter.Rows.Count)
           REM Do While 1=1
            REM 'Msgbox
           REM Loop
        'msgbox "Filtered range has " & rngFilter.Rows.Count & " rows."
            str=""
            For each cel in rngFilter

              str = str & (cel.row) & ":" & (cel.row) & "," 

            Next

                    rangesToRemove = Split(str,",")

                    For x = UBOUND(rangesToRemove)-1 To LBOUND(rangesToRemove) Step -1

                         strToRemove = strToRemove & rangesToRemove(x)

                            If Len(strToRemove) > 200 then

                                ob4.Range(strToRemove).delete'str & rangesToRemove(x) & ":" & rangesToRemove(x) & ","
                                strToRemove = ""

                            Else

                                strToRemove = strToRemove & ","

                            End If

                    Next
                    If len(strToRemove) > 0 then

                        strToRemove = Mid(strToRemove, 1, Len(strToRemove) - 1)
                        'strToRemove = Left(strToRemove, Len(strToRemove) -1)
                        ob4.Range(strToRemove).delete

                    End If

        ob4.AutoFilterMode = False
        objExcel1.ScreenUpdating = True
        objExcel1.Calculation = -4105   'xlCalculationAutomatic

        TotalRows=objExcel1.Application.WorksheetFunction.CountA(ob4.Columns(1))
        'MsgBox(TotalRows)
        ReDim ArrParent(TotalRows - 2)
        ArrParent=ob4.Range("A2:" & "A" & TotalRows).Value
        'Call to the subroutine
        ParentPIDNumber ArrParent,ob3,ob2,ob4

    End Sub

请在这里帮助我！

Answer 1

在这种情况下，您可以做的最好的事情是在单独的脚本中提取错误代码并在那里进行实验，直到找到错误。

在你的情况下，我找不到错误，以下脚本没有错误，但它跳过了数组的最后一个元素

ArrParent = Array(10, 20, 30)
Count=LBound(ArrParent)
Set Dic = CreateObject("Scripting.Dictionary")
Do Until Count > UBound(ArrParent) - 1
  Dic(ArrParent(Count))=Count+2
  Count=Count+1
Loop
for each key in Dic 
  wscript.echo key & ":" & Dic(key)
next

'10:2
'20:3

我没有你的sourcearray进行试验，但你可以这样试试，为了没有索引超出范围错误你可以使用“for each”，如果你不需要count变量it甚至是迭代数组的最好方法。

Count = 1
Set Dic = CreateObject("Scripting.Dictionary")
for each element in ArrParent
  Dic(element)=Count+2
  Count = Count+1
next

for each key in Dic 
  wscript.echo key & ":" & Dic(key)
next
'10:3
'20:4
'30:5

我的VBScript代码“下标超出范围”我收到错误

1 个答案: