Question

在我看来，我得到了points_total，但它返回的所有点都不同于当前用户过滤的points_list。

问题：

1）如何按用户过滤'def points_total'，如'points_list'

model.py

class PointsManager(models.Manager):

    def points_list(self,thisUser):
        list = Points.objects.filter(user=thisUser)
        return list

    def points_total(self,thisUser):
        return Points.objects.aggregate(models.Sum('points'))


class Points (models.Model):

    statusOptions = (
        (0, 'Pending'),
        (1, 'Added'),
        (2, 'Deducted'),
        (3, 'Processing'),
        )

    user = models.ForeignKey(User)
    points = models.IntegerField(verbose_name=("Points"), default=0)
    created = models.DateTimeField(("Created at"), auto_now_add=True)
    updated = models.DateTimeField(verbose_name=("Updated at"), auto_now=True)
    status = models.IntegerField(default=0, choices=statusOptions)

    objects = PointsManager()



    class Meta:
      verbose_name = ('Point')
      verbose_name_plural = ('Points')

Answer 1

首先，我认为你的两个职能部门都不需要经理，你可以直接通过查询模型来实现。

point_list功能

的替代方案

points_list = Points.objects.filter(user=request.user)

points_total功能

的替代方案

points = Points.objects.filter(user=request.user) \
                       .aggregate(total_points=models.Sum('points'))

Django模型：聚合过滤器

1 个答案: