我read this already并写了这个脚本来获取某些邮箱中的电子邮件正文,标题以'$'开头,由一些发件人发送。
import email, getpass, imaplib, os
detach_dir = "F:\PYTHONPROJECTS" # where you will save attachments
user = raw_input("Enter your GMail username --> ")
pwd = getpass.getpass("Enter your password --> ")
# connect to the gmail imap server
m = imaplib.IMAP4_SSL("imap.gmail.com")
m.login(user, pwd)
m.select("PETROLEUM") # here you a can choose a mail box like INBOX instead
# use m.list() to get all the mailboxes
resp, items = m.search(None, '(FROM "EIA_eLists@eia.gov")')
items = items[0].split() # getting the mails id
my_msg = [] # store relevant msgs here in please
msg_cnt = 0
break_ = False
for emailid in items[::-1]:
resp, data = m.fetch(emailid, "(RFC822)")
if ( break_ ):
break
for response_part in data:
if isinstance(response_part, tuple):
msg = email.message_from_string(response_part[1])
varSubject = msg['subject']
if varSubject[0] == '$':
msg_cnt += 1
my_msg.append(msg)
print msg_cnt
print email.message_from_string(response_part[1])
if ( msg_cnt == 5 ):
break_ = True
如果我打印email.message_from_string(response_part[1])
,我可以看到它包含第一个信息(标题,从,到,日期......),全文正文。但是,我无法取得身体本身。 email.message_from_string(response_part[0])
打印邮件IDS,email.message_from_string(response_part[2])
超出范围。 email.message_from_string(response_part[1][0])
也没有这样做。
谢谢和问候。
更新
现在,我几乎可以拥有正文。然而,它仍然被首先出现的信息声明所破坏。我得到了结果
From nobody Tue Dec 25 11:42:58 2012
US=3D$4.030
EastCst=3D$4.036
NewEng=3D$4.205
CenAtl=3D$4.149
LwrAtl=3D$3.921
Midwst=3D$3.984
GulfCst=3D$3.945
RkyMt=3D$4.195
WCst=3D$4.187
CA=3D$4.268
我希望摆脱From nobody Tue Dec 25 11:42:58 2012
这是信息。我知道我可以解析文本寻找第一条相关的行...我知道。
实现目标的代码(插入我的第一个样本)是
if varSubject[0] == '$':
r, d = m.fetch(emailid, "(UID BODY[TEXT])")
msg_cnt += 1
my_msg.append(msg)
print email.message_from_string(d[0][1])
你有更好的方法(没有信息字符串)???更多:现在获取日期的命令是什么?我知道我可以varDate = msg['date']
在上面适合的地方,但是如何才能获取每月 - 每年?致谢
答案 0 :(得分:8)
我已设法使用Gmail工作,它会提取有用位并将其输出到文本文件:
const object = {/**/}
type SomeType = {
foo: string,
bar: bool,
baz: Object,
}
describe('object', () => {
describe('.subfield', () => {
it('conforms to SomeType', () => {
// Here I want to write an 'expect'
// that checks if object.subfield
// conforms to the SomeType flow type?
})
});
});
答案 1 :(得分:5)
您可以通过执行以下任何操作来获取正文的内容
msg.as_string()
str(msg)
repr(msg)
http://docs.python.org/2.7/library/email.message.html#email.message.Message
答案 2 :(得分:0)
from imap_tools import MailBox
# get all attachments from INBOX and save them to files
with MailBox('imap.my.ru').login('acc', 'pwd', 'INBOX') as mailbox:
for msg in mailbox.fetch():
print(msg.text)
print(msg.html)
这将需要外部库,但要简单得多。
答案 3 :(得分:-1)
client.send_message(chat_id, "message") # i want 2 this at 12:00 for example