Question

我正在处理一个图像查看器，所以我有一个名为Viewer的控制器，当我传递它routeValues时，它会像这样在URL中传递： http://www.mywebsite.com/Viewer?category=1&image=2

以下是此页面上的链接：

@Url.Action("Index", new { category = p.Category, image = p.Image })

但我喜欢这个网址： http://www.mywebsite.com/Viewer/1/2

我试图在RegisterRoutes类的RouteConfig方法中做一些技巧，但我无法获得之前的结果。

public class RouteConfig
{
    public static void RegisterRoutes(RouteCollection routes)
    {
        routes.IgnoreRoute("{resource}.axd/{*pathInfo}");

        routes.MapRoute(
            name: "Default",
            url: "{controller}/{action}/{id}",
            defaults: new { controller = "Home", action = "Index", id = UrlParameter.Optional }
        );

        routes.MapRoute(
            name: "Viewer",
            url: "{controller}/{action}/{category}-{image}",
            defaults: new { controller = "Viewer", action = "Index", category = 1, image = 1 }
        );
    }
}

有谁知道我可以在哪里做到这一点？

非常感谢！

Answer 1

您需要在默认路由之前放置更具体的路由，因为路由的评估顺序与您声明的路径相同：

public class RouteConfig
{
    public static void RegisterRoutes(RouteCollection routes)
    {
        routes.IgnoreRoute("{resource}.axd/{*pathInfo}");

        routes.MapRoute(
            name: "Viewer",
            url: "{controller}/{action}/{category}/{image}",
            defaults: new { controller = "Viewer", action = "Index", category = 1, image = 1 }
        );

        routes.MapRoute(
            name: "Default",
            url: "{controller}/{action}/{id}",
            defaults: new { controller = "Home", action = "Index", id = UrlParameter.Optional }
        );
    }
}

在我的ASP .NET MVC网站上重写URL

1 个答案: