Question

我对Python很陌生，想为我的学生编写一个（非计算机）语言培训师。就像计时器在后台运行的地方一样，学生必须快速输入单词以减慢/恢复倒计时 - 否则倒计时到达零并显示一些“游戏结束”消息。（就像特殊的特工必须在定时器向零跑时才能消除炸弹一样。）

有大量的线程解释，这听起来是正确的方法，当然，但到目前为止，我还没有找到任何计时器与（时间限制的）raw_input相结合的地方。你们中的任何一位专业人士都可以给我一个指向我忽略的教程/讨论的指针吗？

Answer 1

import threading
import time
import os

def ask():
    """
    Simple function where you ask him his name, if he answers
    you print message and exit
    """
    name = raw_input("Tell me your name, you have 5 seconds: ")
    exit_message = "Wohoho you did it..Your name is %s" % name
    exit(exit_message)

def exit(msg):
    """
    Exit function, prints something and then exits using OS
    Please note you cannot use sys.exit when threading..
    You need to use os._exit instead
    """
    print(msg)
    os._exit(1)

def close_if_time_pass(seconds):
    """
    Threading function, after N seconds print something and exit program
    """
    time.sleep(seconds)
    exit("Time passed, I still don't know your name..")

def main():
    # define close_if_time_pass as a threading function, 5 as an argument
    t = threading.Thread(target=close_if_time_pass,args=(5,))
    # start threading
    t.start()
    # ask him his name
    ask()

if __name__ == "__main__":
    main()

Answer 2

您不必通过线程进行操作，您可以在单个线程中以特定频率运行“逻辑”，并且每次迭代都会通过时间增量方法重新计算倒计时。这是制作了多少个视频游戏。

假设您在60hz运行此伪代码方法：

delta = timenow-timelast;
countdown -= delta;
if(input)
    processInputHere;

您应该能够将伪代码转换为python代码以使其正常工作

输入时间限制/倒计时

2 个答案: