我创建了一个字典,并在数组中添加了字典和字典中的名称键值数据,使用for循环来迭代数据。但我想搜索名称为vinod.below的密钥名字是我的代码。
NSDictionary *dic2 =[[NSDictionary alloc] init];
NSDictionary *dic1 =[[NSDictionary alloc] init];
[dic1 setValue:@"Vinod" forKey:@"fname"];
[dic2 setValue:@"vishw" forKey:@"lname"];
[dic2 setValue:@"Tazeen" forKey:@"fname"];
[dic2 setValue:@"momin" forKey:@"lname"];
NSMutableArray *arr =[[NSMutableArray alloc] initWithObjects:dic1,dic2, nil];
NSLog(@"inside the view did load");
NSMutableArray *arr2=[[NSMutableArray alloc] init];
for (int i=0; i<[arr count]; i++)
{
NSString *str =[arr objectAtIndex:i];
NSLog(@"inside the loop");
[arr2 addObject:str];
// NSArray *arr =[[NSArray alloc] initWithObjects:str, nil];
if ([arr2 containsObject:@"vinod"])
{
NSLog(@"first name found in the array");
}
}
提前致谢
答案 0 :(得分:3)
您的代码包含一些愚蠢的错误,例如向不可变字典添加值。
我已更正并找到代码:
NSMutableDictionary *dic2 =[[NSMutableDictionary alloc] init];
NSMutableDictionary *dic1 =[[NSMutableDictionary alloc] init];
[dic1 setValue:@"Vinod" forKey:@"fname"];
[dic2 setValue:@"vishw" forKey:@"lname"];
[dic2 setValue:@"Tazeen" forKey:@"fname"];
[dic2 setValue:@"momin" forKey:@"lname"];
NSMutableArray *arr =[[NSMutableArray alloc] initWithObjects:dic1,dic2, nil];
for (NSDictionary *dictObj in arr) {
if ([[dictObj valueForKey:@"fname"]isEqualToString:@"Vinod"]) {
NSLog(@"name found");
}
}
答案 1 :(得分:0)
好的......或许完整的重写是有序的。你的代码既复杂又简单,在某些地方也是如此,我在下面已经提到过。
NSMutableDictionary *dic1 =[[NSMutableDictionary alloc] init]; //Your dictionary needs to
//be mutable, otherwise it will throw exceptions.
//NSDictionary is immutable.
NSMutableDictionary *dic2 =[[NSMutableDictionary alloc] init];
[dic1 setValue:@"Vinod" forKey:@"fname"];
[dic1 setValue:@"vishw" forKey:@"lname"];
[dic2 setValue:@"Tazeen" forKey:@"fname"];
[dic2 setValue:@"momin" forKey:@"lname"];
//Add all the values from the dictionaries into one master array.
NSMutableArray *arr =[[NSMutableArray alloc] init];
[arr addObjectsFromArray:[dic1 allValues]];
[arr addObjectsFromArray:[dic2 allValues]];
NSLog(@"inside the view did load");
//load those values into a set for faster lookup
NSSet *set = [[NSSet alloc]initWithArray:arr];
//For-in the values. Fast enumeration is a lot better at this than c-loops
for (NSString *value in arr) {
if ([set containsObject:@"Vinod"]) {
NSLog(@"first name found in the array");
}
}
答案 2 :(得分:0)
我希望这会对您有所帮助,此示例代码使用NSFastEnumeration与阻止。
NSDictionary *dic2 =[[NSDictionary alloc] init];
NSDictionary *dic1 =[[NSDictionary alloc] init];
[dic1 setValue:@"Vinod" forKey:@"fname"];
[dic2 setValue:@"vishw" forKey:@"lname"];
[dic2 setValue:@"Tazeen" forKey:@"fname"];
[dic2 setValue:@"momin" forKey:@"lname"];
NSMutableArray *arr =[[NSMutableArray alloc] initWithObjects:dic1,dic2, nil];
NSLog(@"inside the view did load");
[arr enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
if ([[obj valueForKey:@"fname"] isEqual:@"Vinod"]) {
NSLog(@"Found it!");
*stop = YES;
}
}];
答案 3 :(得分:0)
“试试这个: -
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"fname = %@",@"Vinod];
NSMutableArray *aMutArray = [NSMutableArray arrayWithArray:aYourArray];
[aMutArray filterUsingPredicate:predicate];
NSMutableDictionary *aDictTemp = [aMutArray objectAtIndex:0];
通常NSPredicate用于过滤掉数组或在数组内搜索。有关详细信息,请查看此链接: -