如何加载Spring资源内容并使用它来设置bean属性或将其作为参数构造函数传递?
资源包含自由文本。
答案 0 :(得分:31)
<bean id="contents" class="org.apache.commons.io.IOUtils" factory-method="toString">
<constructor-arg value="classpath:path/to/resource.txt" type="java.io.InputStream" />
</bean>
此解决方案需要Apache Commons IO。
@Parvez建议的另一个没有Apache Commons IO依赖的解决方案是
<bean id="contents" class="java.lang.String">
<constructor-arg>
<bean class="org.springframework.util.FileCopyUtils" factory-method="copyToByteArray">
<constructor-arg value="classpath:path/to/resource.txt" type="java.io.InputStream" />
</bean>
</constructor-arg>
</bean>
答案 1 :(得分:21)
在一行中尝试阅读test.xml:
def ecpd(request):
r= requests.get('http://jira.xxx.xxx.com/rest/api/2/issue/key-XXX',auth=HTTPBasicAuth('user','pass'),headers = {'Content-Type' : 'application/json'})
if r.status_code == 200:
jsonDict = r.json()
return HttpResponse(jsonDict)
答案 2 :(得分:12)
请阅读:
try {
Resource resource = new ClassPathResource(fileLocationInClasspath);
BufferedReader br = new BufferedReader(new InputStreamReader(resource.getInputStream()),1024);
StringBuilder stringBuilder = new StringBuilder();
String line;
while ((line = br.readLine()) != null) {
stringBuilder.append(line).append('\n');
}
br.close();
return stringBuilder.toString();
} catch (Exception e) {
LOGGER.error(e);
}
答案 3 :(得分:4)
这是一种不使用任何外部库的方法。默认由spring提供.. environment.properties文件包含键值对...用$ {key}引用每个值
在我的例子中,我保留了数据库道具
<bean id="propertyConfigurer"
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="locations">
<list value-type="org.springframework.core.io.Resource">
<value>classpath:environment.properties</value>
</list>
</property>
</bean>
<bean id="mySQLdataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="${JDBC.driver}" />
<property name="url" value="${JDBC.URL}" />
<property name="username" value="${JDBC.username}" />
<property name="password" value="${JDBC.password}" />
</bean>
答案 4 :(得分:1)
daoway回答非常有帮助,并且在Adrian评论之后我添加了一个类似于daoway代码的配置代码段
<bean id="contents" class="org.springframework.core.io.ClassPathResource">
<constructor-arg value="path/to/resource.txt"/>
</bean>
从您的组件
@Autowired
private Resource contents;
@PostConstruct
public void load(){
try {
final InputStream inputStream = contents.getInputStream();
//use the stream
BufferedReader br = new BufferedReader(new InputStreamReader(inputStream ,1024);
StringBuilder stringBuilder = new StringBuilder();
String line;
while ((line = br.readLine()) != null) {
stringBuilder.append(line).append('\n');
}
br.close();
}catch (IOException e) {
LOGGER.error(message);
}
}
答案 5 :(得分:1)
春天
private String readResource(String fileName){
ResourceLoader resourceLoader = new DefaultResourceLoader();
Resource resource = resourceLoader.getResource("resourceSubfolder/"+fileName)
try{
Reader reader = new InputStreamReader(resource.getInputStream());
return FileCopyUtils.copyToString(reader);
} catch (IOException e){
e.printStackTrace();
}
return null;
}