ios6中的SQLCipher架构armv7s的未定义符号（架构已更改）

Question

使用 xcode 4.5.2 构建 sqlcipher 时遇到问题。基本上我遵循了http://mobileorchard.com/tutorial-iphone-sqlite-encryption-with-sqlcipher/和http://sqlcipher.net/ios-tutorial/的示例。不幸的是，我最后得到一条消息，告诉我ssl lib和sqlcipher lib不是为armv7s构建的。

错误讯息：

ld: warning: ignoring file /Users/jeven/Library/Developer/<...>/Debug-iphoneos/libsqlcipher.a, file was built for archive which is not the architecture being linked (armv7s): /Users/jeven/Library/Developer/<...>/Debug-iphoneos/libsqlcipher.a
ld: warning: ignoring file /Users/jeven/Library/Developer/<...>/Debug-iphoneos/libcrypto.a, file was built for archive which is not the architecture being linked (armv7s): /Users/jeven/Library/Developer/<...>/Debug-iphoneos/libcrypto.a

Undefined symbols for architecture armv7s:
      "_sqlite3_prepare_v2", referenced from:
...

我知道这已发布了几次，但我已经更改了openssl和sqlcipher项目的目标架构，正如您在下面的屏幕截图中看到的那样。

OpenSSL的： 的 sqlcipher ：

我真的有点被困在这里:(有人对我有暗示吗？

Answer 1

尝试将仅调试的构建活动架构设置为NO！ change either config of openssl and sqlcipher

Answer 2

之前我遇到过类似的问题，尝试删除armv7s并只留下armv7

Answer 3

将 libsqlite3.dylib 添加到构建阶段＆＃39;列表清单。

选择您的项目目标 - ＆gt;建立阶段：

将 libsqlite3.dylib 添加到将二进制文件链接到库