Question

如何在数组中找到第二高的数字

Answer 1

function getSecondHighest(arrCheck){
    var first=0,second=0;
    for(var i=0;i<arrCheck.length;i++){
        if(arrCheck[i] > first){
            second = first;
            first = arrCheck[i];
        }
        else if(arrCheck[i]>second && arrCheck[i]<first){
            second = arrCheck[i];
       } 
    }
    return second;
}

Answer 2

如果你经历一次列表;你会找到最高的数字。现在重复这一次，你将获得第二高的数字。

Answer 3

function max(a){
var big = a[0];
var secondLargest =null;
for(var i=0;i<a.length;i++){
if(a[i]>big){
secondLargest = big;
big=a[i];
}else if(a[i]>secondLargest){
secondLargest =a[i];
}
}
return secondLargest;
}

Answer 4

见：

var array = [267, 306, 108, 50, 909, 200];
var newCopy = [0];
for (i = 0; i < array.length; i++) {
newCopy[i] = array[i];
}
var largest = Math.max.apply(Math, newCopy);
newCopy.splice(newCopy.indexOf(largest), 1);
largest = Math.max.apply(Math, newCopy);
alert(largest);

如何在javascript中找到第二高的数字

4 个答案: