Question

当我尝试在下面执行写入文件时，我收到错误，如下所示......我做错了什么？

# create a method that writes to a file.

f = open("C:\Users\QamarAli\Documents\afaq's stuff\myFile.txt", "r+")
f.write('0123456789abcdef')

这是错误：

Traceback (most recent call last):
  File "<interactive input>", line 1, in <module>
IOError: [Errno 22] invalid mode ('r+') or filename: "C:\\Users\\QamarAli\\Documents\x07faq's stuff\\myFile.txt"
>>>

Answer 1

尝试使用os.path和os.sep在Windows上构建文件路径：

import os

file_path = os.path.join("C:" + os.sep, "Users", "QamarAli", "Documents", "afaq's stuff", "myFile.txt")
print file_path
print os.path.exists(file_path)

Answer 2

\a是一个转义序列（看看你的文件名中发生了什么）。使用Windows路径时使用raw strings告诉Python不要解释反斜杠转义序列：

r"C:\Users\QamarAli\Documents\afaq's stuff\myFile.txt"
^ add this thing

Answer 3

f = open("C:\Users\QamarAli\Documents\afaq's stuff\myFile.txt", "a+")
f.write('0123456789abcdef')

而不是试试这个：

import os
f = open(os.path.join("C:\\", "Users", "QamarAli", "Documents", "afaq's stuff", "myFile.txt"),  "r+")
f.write('0123456789abcdef')
f.close()

确保该文件已存在，且路径有效。

我现在也看到了这一点，看来你可能正在使用错误的路径，看看ineterpreter给你的错误。而不是afaq's stuff它说x07faq's stuff加上它是我看到单一斜线的唯一地方。我认为我同意搅拌机你提出的路径不对。

Answer 4

在路径中使用正斜杠。

f = open("C:/Users/QamarAli/Documents/afaq's stuff/myFile.txt", "r+")
f.write('0123456789abcdef')

在Python中写入文件时出现IOError

4 个答案: