类方法调用第一次运行正常,但在退出活动并尝试第二次运行计算后非常慢

时间:2012-12-23 01:02:16

标签: java android class methods static

好的,所以这就是问题所在:

我正在制作一个随机生成地形的游戏。地形生成一次并保存到磁盘/ SD卡。它做得非常好:)

要做到这一点,我运行一个SplashScreenActivity来运行我的开始启动画面,世界创建或世界加载,具体取决于它的启动方式。 实际的程序生成是使用4D Simplex Noise完成的,使用由Stefan Gustavson编写的类,由Peter Eastman编写(并由我自己优化和加速至少50%,将变量拉出来并使它们变得静止......但问题是我即将描述在这些变化之前发生的事情。

基本上我使用他们的噪音功能来填充有噪音的瓷砖。在我的世界创建循环中,我循环遍历所有像素,每个图块遍历所有像素,调用类的SimplexNoise4D.noise(x,y,z,w)函数来填充每个像素(我正在计划发送类的xyzw-pixel-collection集合,因此它可以运行该方法以便更快地访问。)

无论如何,这一切都很有效。但是当我退出游戏活动并返回主菜单时,如果我再次尝试运行世界创建,则访问SimplexNoise类方法(.noise方法及其使用的内部方法)是缓慢的! 使调用以正常速度运行的唯一方法是退出整个应用程序(使用任务管理器终止它)并重新启动应用程序。然后,第一次运行它时,平铺创建速度应尽可能快。 使用调试/方法profilling等,似乎对.noise方法的调用以及对dot方法的调用在第二次尝试运行整个世界创建时花费了大量时间。

所以,再次,我第一次使用SimplexNoise.noise(xyzw)进行循环访问,它运行正常。然后第二次访问所有图块中的所有像素(在游戏之后),并且对该类的所有方法调用都需要FOREVER。

有谁知道为什么会发生这种情况以及如何阻止它发生?

CNC中 只是为了清理,应用程序的工作方式如下: mainmenuActivity - > chooseWorldSizeActivity-> Splashscreen,通过大量调用SimplexNoise.noise(xywz)创建世界 - >退出splashscreen->开始游戏活动。

这很好,而且速度很快。 但是,如果我退出gameActivity(进入主菜单),然后 - > gt; selectWordlSizeActivity-> splashscreenActivity,现在对SimplexNoise.noise(xyzw)的调用将永远完成。 如果我停止整个应用程序(使用atskkiller),则世界创建需要正常时间再次运行。我无法找到原因! - /编辑 -

调用循环(在ASyncTask的doInBackground()中)就是:

for(loop over rows of tiles)
    for(loop over column tiles)
        for(each pixel)
             create x, y, z, w;
             SimplexNoise.noise(xyzw);

Simplex Noise类如下所示:

`

public final class SimplexNoise4D {  // Simplex noise in 2D, 3D and 4D
  private static final Grad grad3[] = {new Grad(1,1,0),new Grad(-1,1,0),new Grad(1,-1,0),new Grad(-1,-1,0),
                                 new Grad(1,0,1),new Grad(-1,0,1),new Grad(1,0,-1),new Grad(-1,0,-1),
                                 new Grad(0,1,1),new Grad(0,-1,1),new Grad(0,1,-1),new Grad(0,-1,-1)};

  private static final Grad grad4[]= {new Grad(0,1,1,1),new Grad(0,1,1,-1),new Grad(0,1,-1,1),new Grad(0,1,-1,-1),
                   new Grad(0,-1,1,1),new Grad(0,-1,1,-1),new Grad(0,-1,-1,1),new Grad(0,-1,-1,-1),
                   new Grad(1,0,1,1),new Grad(1,0,1,-1),new Grad(1,0,-1,1),new Grad(1,0,-1,-1),
                   new Grad(-1,0,1,1),new Grad(-1,0,1,-1),new Grad(-1,0,-1,1),new Grad(-1,0,-1,-1),
                   new Grad(1,1,0,1),new Grad(1,1,0,-1),new Grad(1,-1,0,1),new Grad(1,-1,0,-1),
                   new Grad(-1,1,0,1),new Grad(-1,1,0,-1),new Grad(-1,-1,0,1),new Grad(-1,-1,0,-1),
                   new Grad(1,1,1,0),new Grad(1,1,-1,0),new Grad(1,-1,1,0),new Grad(1,-1,-1,0),
                   new Grad(-1,1,1,0),new Grad(-1,1,-1,0),new Grad(-1,-1,1,0),new Grad(-1,-1,-1,0)};

  private static final short p[] = {151,160,137,91,90,15,
  131,13,201,95,96,53,194,233,7,225,140,36,103,30,69,142,8,99,37,240,21,10,23,
  190, 6,148,247,120,234,75,0,26,197,62,94,252,219,203,117,35,11,32,57,177,33,
  88,237,149,56,87,174,20,125,136,171,168, 68,175,74,165,71,134,139,48,27,166,
  77,146,158,231,83,111,229,122,60,211,133,230,220,105,92,41,55,46,245,40,244,
  102,143,54, 65,25,63,161, 1,216,80,73,209,76,132,187,208, 89,18,169,200,196,
  135,130,116,188,159,86,164,100,109,198,173,186, 3,64,52,217,226,250,124,123,
  5,202,38,147,118,126,255,82,85,212,207,206,59,227,47,16,58,17,182,189,28,42,
  223,183,170,213,119,248,152, 2,44,154,163, 70,221,153,101,155,167, 43,172,9,
  129,22,39,253, 19,98,108,110,79,113,224,232,178,185, 112,104,218,246,97,228,
  251,34,242,193,238,210,144,12,191,179,162,241, 81,51,145,235,249,14,239,107,
  49,192,214, 31,181,199,106,157,184, 84,204,176,115,121,50,45,127, 4,150,254,
  138,236,205,93,222,114,67,29,24,72,243,141,128,195,78,66,215,61,156,180};
  // To remove the need for index wrapping, double the permutation table length
  private static short perm[] = new short[512];
  private static short permMod12[] = new short[512];
  static {
    for(int i=0; i<512; i++)
    {
      perm[i]=p[i & 255];
      permMod12[i] = (short)(perm[i] % 12);
    }
  }

  // Skewing and unskewing factors for 2, 3, and 4 dimensions
  private static final double F2 = 0.5*(Math.sqrt(3.0)-1.0);
  private static final double G2 = (3.0-Math.sqrt(3.0))/6.0;
  private static final double F3 = 1.0/3.0;
  private static final double G3 = 1.0/6.0;
  private static final double F4 = (Math.sqrt(5.0)-1.0)/4.0;
  private static final double G4 = (5.0-Math.sqrt(5.0))/20.0;

  // This method is a *lot* faster than using (int)Math.floor(x)
  private static int fastfloor(double x) {
    int xi = (int)x;
    return x<xi ? xi-1 : xi;
  }

  private static double dot(Grad g, double x, double y) {
    return g.x*x + g.y*y; }

  private static double dot(Grad g, double x, double y, double z) {
    return g.x*x + g.y*y + g.z*z; }

  private static double dot(Grad g, double x, double y, double z, double w) {
    return g.x*x + g.y*y + g.z*z + g.w*w; }

  private static double n0, n1, n2, n3, n4; // Noise contributions from the five corners
  private static double s;// Factor for 4D skewing
  private static int i;
  private static int j;
  private static int k;
  private static int l;
  private static double t; // Factor for 4D unskewing
  private static double X0; // Unskew the cell origin back to (x,y,z,w) space
  private static double Y0;
  private static double Z0;
  private static double W0;
  private static double x0;  // The x,y,z,w distances from the cell origin
  private static double y0;
  private static double z0;
  private static double w0;
  private static int rankx;
  private static int ranky;
  private static int rankz;
  private static int rankw;
  private static int i1, j1, k1, l1; // The integer offsets for the second simplex corner
  private static int i2, j2, k2, l2; // The integer offsets for the third simplex corner
  private static int i3, j3, k3, l3; // The integer offsets for the fourth simplex corner
  private static double x1; // Offsets for second corner in (x,y,z,w) coords
  private static double y1;
  private static double z1;
  private static double w1;
  private static double x2; // Offsets for third corner in (x,y,z,w) coords
  private static double y2;
  private static double z2;
  private static double w2;
  private static double x3; // Offsets for fourth corner in (x,y,z,w) coords
  private static double y3;
  private static double z3;
  private static double w3;
  private static double x4; // Offsets for last corner in (x,y,z,w) coords
  private static double y4;
  private static double z4;
  private static double w4;
  // Work out the hashed gradient indices of the five simplex corners
  private static int ii;
  private static int jj;
  private static int kk;
  private static int ll;
  private static int gi0;
  private static int gi1;
  private static int gi2;
  private static int gi3;
  private static int gi4;

  private static double t0;
  private static double t1;
  private static double t2;
  private static double t3;
  private static double t4;

  // 4D simplex noise, better simplex rank ordering method 2012-03-09
  public static double noise(double x, double y, double z, double w) {

    ////double n0, n1, n2, n3, n4; // Noise contributions from the five corners
    // Skew the (x,y,z,w) space to determine which cell of 24 simplices we're in
    ////double s = (x + y + z + w) * F4; // Factor for 4D skewing
    s = (x + y + z + w) * F4; // Factor for 4D skewing
    /*int i = fastfloor(x + s);
    int j = fastfloor(y + s);
    int k = fastfloor(z + s);
    int l = fastfloor(w + s);
    double t = (i + j + k + l) * G4; // Factor for 4D unskewing
    double X0 = i - t; // Unskew the cell origin back to (x,y,z,w) space
    double Y0 = j - t;
    double Z0 = k - t;
    double W0 = l - t;
    double x0 = x - X0;  // The x,y,z,w distances from the cell origin
    double y0 = y - Y0;
    double z0 = z - Z0;
    double w0 = w - W0;*/
    i = fastfloor(x + s);
    j = fastfloor(y + s);
    k = fastfloor(z + s);
    l = fastfloor(w + s);
    t = (i + j + k + l) * G4; // Factor for 4D unskewing
    X0 = i - t; // Unskew the cell origin back to (x,y,z,w) space
    Y0 = j - t;
    Z0 = k - t;
    W0 = l - t;
    x0 = x - X0;  // The x,y,z,w distances from the cell origin
    y0 = y - Y0;
    z0 = z - Z0;
    w0 = w - W0;
    // For the 4D case, the simplex is a 4D shape I won't even try to describe.
    // To find out which of the 24 possible simplices we're in, we need to
    // determine the magnitude ordering of x0, y0, z0 and w0.
    // Six pair-wise comparisons are performed between each possible pair
    // of the four coordinates, and the results are used to rank the numbers.
    /*int rankx = 0;
      int ranky = 0;
      int rankz = 0;
      int rankw = 0;
      if(x0 > y0) rankx++; else ranky++;
      if(x0 > z0) rankx++; else rankz++;
      if(x0 > w0) rankx++; else rankw++;
      if(y0 > z0) ranky++; else rankz++;
      if(y0 > w0) ranky++; else rankw++;
      if(z0 > w0) rankz++; else rankw++;
      int i1, j1, k1, l1; // The integer offsets for the second simplex corner
      int i2, j2, k2, l2; // The integer offsets for the third simplex corner
      int i3, j3, k3, l3; // The integer offsets for the fourth simplex corner*/
    rankx = 0;
    ranky = 0;
    rankz = 0;
    rankw = 0;
    if(x0 > y0) rankx++; else ranky++;
    if(x0 > z0) rankx++; else rankz++;
    if(x0 > w0) rankx++; else rankw++;
    if(y0 > z0) ranky++; else rankz++;
    if(y0 > w0) ranky++; else rankw++;
    if(z0 > w0) rankz++; else rankw++;
    // simplex[c] is a 4-vector with the numbers 0, 1, 2 and 3 in some order.
    // Many values of c will never occur, since e.g. x>y>z>w makes x<z, y<w and x<w
    // impossible. Only the 24 indices which have non-zero entries make any sense.
    // We use a thresholding to set the coordinates in turn from the largest magnitude.
    // Rank 3 denotes the largest coordinate.
    i1 = rankx >= 3 ? 1 : 0;
    j1 = ranky >= 3 ? 1 : 0;
    k1 = rankz >= 3 ? 1 : 0;
    l1 = rankw >= 3 ? 1 : 0;
    // Rank 2 denotes the second largest coordinate.
    i2 = rankx >= 2 ? 1 : 0;
    j2 = ranky >= 2 ? 1 : 0;
    k2 = rankz >= 2 ? 1 : 0;
    l2 = rankw >= 2 ? 1 : 0;
    // Rank 1 denotes the second smallest coordinate.
    i3 = rankx >= 1 ? 1 : 0;
    j3 = ranky >= 1 ? 1 : 0;
    k3 = rankz >= 1 ? 1 : 0;
    l3 = rankw >= 1 ? 1 : 0;
    // The fifth corner has all coordinate offsets = 1, so no need to compute that.
    /*double x1 = x0 - i1 + G4; // Offsets for second corner in (x,y,z,w) coords
    double y1 = y0 - j1 + G4;
    double z1 = z0 - k1 + G4;
    double w1 = w0 - l1 + G4;
    double x2 = x0 - i2 + 2.0*G4; // Offsets for third corner in (x,y,z,w) coords
    double y2 = y0 - j2 + 2.0*G4;
    double z2 = z0 - k2 + 2.0*G4;
    double w2 = w0 - l2 + 2.0*G4;
    double x3 = x0 - i3 + 3.0*G4; // Offsets for fourth corner in (x,y,z,w) coords
    double y3 = y0 - j3 + 3.0*G4;
    double z3 = z0 - k3 + 3.0*G4;
    double w3 = w0 - l3 + 3.0*G4;
    double x4 = x0 - 1.0 + 4.0*G4; // Offsets for last corner in (x,y,z,w) coords
    double y4 = y0 - 1.0 + 4.0*G4;
    double z4 = z0 - 1.0 + 4.0*G4;
    double w4 = w0 - 1.0 + 4.0*G4;
    // Work out the hashed gradient indices of the five simplex corners
    int ii = i & 255;
    int jj = j & 255;
    int kk = k & 255;
    int ll = l & 255;
    int gi0 = perm[ii+perm[jj+perm[kk+perm[ll]]]] % 32;
    int gi1 = perm[ii+i1+perm[jj+j1+perm[kk+k1+perm[ll+l1]]]] % 32;
    int gi2 = perm[ii+i2+perm[jj+j2+perm[kk+k2+perm[ll+l2]]]] % 32;
    int gi3 = perm[ii+i3+perm[jj+j3+perm[kk+k3+perm[ll+l3]]]] % 32;
    int gi4 = perm[ii+1+perm[jj+1+perm[kk+1+perm[ll+1]]]] % 32;*/
    x1 = x0 - i1 + G4; // Offsets for second corner in (x,y,z,w) coords
    y1 = y0 - j1 + G4;
    z1 = z0 - k1 + G4;
    w1 = w0 - l1 + G4;
    x2 = x0 - i2 + 2.0*G4; // Offsets for third corner in (x,y,z,w) coords
    y2 = y0 - j2 + 2.0*G4;
    z2 = z0 - k2 + 2.0*G4;
    w2 = w0 - l2 + 2.0*G4;
    x3 = x0 - i3 + 3.0*G4; // Offsets for fourth corner in (x,y,z,w) coords
    y3 = y0 - j3 + 3.0*G4;
    z3 = z0 - k3 + 3.0*G4;
    w3 = w0 - l3 + 3.0*G4;
    x4 = x0 - 1.0 + 4.0*G4; // Offsets for last corner in (x,y,z,w) coords
    y4 = y0 - 1.0 + 4.0*G4;
    z4 = z0 - 1.0 + 4.0*G4;
    w4 = w0 - 1.0 + 4.0*G4;
    // Work out the hashed gradient indices of the five simplex corners
    ii = i & 255;
    jj = j & 255;
    kk = k & 255;
    ll = l & 255;
    gi0 = perm[ii+perm[jj+perm[kk+perm[ll]]]] % 32;
    gi1 = perm[ii+i1+perm[jj+j1+perm[kk+k1+perm[ll+l1]]]] % 32;
    gi2 = perm[ii+i2+perm[jj+j2+perm[kk+k2+perm[ll+l2]]]] % 32;
    gi3 = perm[ii+i3+perm[jj+j3+perm[kk+k3+perm[ll+l3]]]] % 32;
    gi4 = perm[ii+1+perm[jj+1+perm[kk+1+perm[ll+1]]]] % 32;

    // Calculate the contribution from the five corners
    /*double t0 = 0.6 - x0*x0 - y0*y0 - z0*z0 - w0*w0;
    if(t0<0) n0 = 0.0;
    else {
      t0 *= t0;
      n0 = t0 * t0 * dot(grad4[gi0], x0, y0, z0, w0);
    }
   double t1 = 0.6 - x1*x1 - y1*y1 - z1*z1 - w1*w1;
    if(t1<0) n1 = 0.0;
    else {
      t1 *= t1;
      n1 = t1 * t1 * dot(grad4[gi1], x1, y1, z1, w1);
    }
   double t2 = 0.6 - x2*x2 - y2*y2 - z2*z2 - w2*w2;
    if(t2<0) n2 = 0.0;
    else {
      t2 *= t2;
      n2 = t2 * t2 * dot(grad4[gi2], x2, y2, z2, w2);
    }
   double t3 = 0.6 - x3*x3 - y3*y3 - z3*z3 - w3*w3;
    if(t3<0) n3 = 0.0;
    else {
      t3 *= t3;
      n3 = t3 * t3 * dot(grad4[gi3], x3, y3, z3, w3);
    }
   double t4 = 0.6 - x4*x4 - y4*y4 - z4*z4 - w4*w4;
    if(t4<0) n4 = 0.0;
    else {
      t4 *= t4;
      n4 = t4 * t4 * dot(grad4[gi4], x4, y4, z4, w4);
    }*/    
    t0 = 0.6 - x0*x0 - y0*y0 - z0*z0 - w0*w0;
    if(t0<0) n0 = 0.0;
    else {
      t0 *= t0;
      n0 = t0 * t0 * dot(grad4[gi0], x0, y0, z0, w0);
    }
   t1 = 0.6 - x1*x1 - y1*y1 - z1*z1 - w1*w1;
    if(t1<0) n1 = 0.0;
    else {
      t1 *= t1;
      n1 = t1 * t1 * dot(grad4[gi1], x1, y1, z1, w1);
    }
   t2 = 0.6 - x2*x2 - y2*y2 - z2*z2 - w2*w2;
    if(t2<0) n2 = 0.0;
    else {
      t2 *= t2;
      n2 = t2 * t2 * dot(grad4[gi2], x2, y2, z2, w2);
    }
   t3 = 0.6 - x3*x3 - y3*y3 - z3*z3 - w3*w3;
    if(t3<0) n3 = 0.0;
    else {
      t3 *= t3;
      n3 = t3 * t3 * dot(grad4[gi3], x3, y3, z3, w3);
    }
   t4 = 0.6 - x4*x4 - y4*y4 - z4*z4 - w4*w4;
    if(t4<0) n4 = 0.0;
    else {
      t4 *= t4;
      n4 = t4 * t4 * dot(grad4[gi4], x4, y4, z4, w4);
    }
    // Sum up and scale the result to cover the range [-1,1]
    return 27.0 * (n0 + n1 + n2 + n3 + n4);
  }

  // Inner class to speed up gradient computations
  // (array access is a lot slower than member access)
  private static class Grad
  {
    double x, y, z, w;

    Grad(double x, double y, double z)
    {
      this.x = x;
      this.y = y;
      this.z = z;
    }

    Grad(double x, double y, double z, double w)
    {
      this.x = x;
      this.y = y;
      this.z = z;
      this.w = w;
    }
  }
}

`

0 个答案:

没有答案