Question

我正在使用包XML和HTML进行一些网页抓取，我需要隔离国家/地区名称，以及您在下面看到的两个数值：

<tr><td>Tonga</td>

    <td class="RightAlign">3,000</td>

    <td class="RightAlign">6,000</td>


    </tr>

这是我到目前为止编写的代码 - 我认为我只需要正确的正则表达式？

# a vector to store the results
pages<-character(0)
country_names<-character(0)

# go through all 6 pages containing the info we want, and store
# the html in a list
for (page in 1:6) {
  who_search <- paste(who_url, page, '.html', sep='')
  page = htmlTreeParse(who_search, useInternalNodes = T)
  pages=c(page, pages)

  # extract the country names of each tweet
  country <- xpathSApply(page, "????", xmlValue)

  country_names<-c(country, country_names)
}

Answer 1

此处无需使用xmlSpathApply，而是使用readHTMLTable

library(XML)
library(RCurl)
page = htmlParse('http://www.who.int/diabetes/facts/world_figures/en/index4.html')
readHTMLTable(page)

                                              Country       2000       2030
1                                               Albania     86,000    188,000
2                                                Andora      6,000     18,000
3                                               Armenia    120,000    206,000
4                                               Austria    239,000    366,000
5                                            Azerbaijan    337,000    733,000
6                                               Belarus    735,000    922,000

使用xpathSApply（注意使用gsub来清理结果）

country <- xpathSApply(page, '//*[@id="primary"]/table/tbody/tr', 
                         function(x) gsub('\n','' ,xmlValue(x))
+ )
> country
 [1] "Albania        86,000        188,000        "                                                  
 [2] "Andora        6,000        18,000        "                                                     
 [3] "Armenia        120,000        206,000        "                                                 
 [4] "Austria        239,000        366,000        "                                                 
 [5] "Azerbaijan        337,000        733,000        "

编辑正如评论中所提到的，我们可以使用xpathSApply而不使用gsub

    val = xpathSApply(page, '//tbody/tr/td', xmlValue) ##gets a vector of table   
    as.data.frame(matrix(val, ncol=3, byrow=TRUE)) ##transform to matrix

使用xpathSApply进行Web抓取

1 个答案: