Question

我正在尝试删除XML文档中的空元素。我希望id31，id32和id33在空时删除。下面是XSLT输出的示例。我正在尝试使用下面的XSLT，但我没有运气。关于我做错了什么的任何想法？感谢

数据

<Item type="Part AML">
    <related_id>
      <Item type="Manufacturer Part">
        <id keyed_name="1234" type="Manufacturer Part"></id>
        <manufacturer keyed_name="Bobs Workshop" type="Manufacturer"></manufacturer>
        <item_number>1234</item_number>
      </Item>
    </related_id>
  </Item>
  <Item type="Part Document">
    <related_id keyed_name="D000005" type="Document">
      <Item type="Document">
        <id keyed_name="D000005" type="Document"></id>
        <major_rev>B</major_rev>
        <name>Firmware 8-16-12</name>
        <item_number>D000005</item_number>
      </Item>
    </related_id>
  </Item>
  <Item type="Part Document">
    <related_id keyed_name="D000003" type="Document">
      <Item type="Document">
        <id keyed_name="D000003" type="Document"></id>
        <major_rev>A</major_rev>
        <name>Design Spec</name>
        <item_number>D000003</item_number>
      </Item>
    </related_id>
  </Item>

输出

 <td width="5%" align="center" uniqueID="ms__id31"></td>
 <td width="13%" align="center" uniqueID="ms__id32"></td>
 <td width="13%" align="center" uniqueID="ms__id33"></td>
 <td width="5%" align="center" uniqueID="ms__id34">D000003</td>
 <td width="13%" align="center" uniqueID="ms__id35">Design Spec</td>
 <td width="8%" align="center" uniqueID="ms__id36">A</td>

论坛代码

  <xsl:template match="node()|@*">
   <xsl:copy>
     <xsl:apply-templates select="node()|@*"/>
 </xsl:copy>
   </xsl:template>

<xsl:template match="*[not(@*|*|comment()|processing-instruction()) and normalize-space()='']"/>

我的XSLT

<xsl:template match="Item[@type='Part AML']|Item[@type='Part Document']">
<tr>
  <td width="5%" align="center" uniqueID="ms__id31">
    <xsl:value-of select="state"/>
  </td>
  <td width="13%" align="center" uniqueID="ms__id32">
    <xsl:value-of select="related_id[@type='Manufacturer Part']/Item/manufacturer/@keyed_name"/>
  </td>
  <td width="13%" align="center" uniqueID="ms__id33">
    <xsl:value-of select="related_id[@type='Manufacturer Part']/Item/item_number"></xsl:value-of>
  </td>
    <td width="13%" align="center" uniqueID="ms__id34">
        <xsl:value-of select="related_id[@type='Document']/Item/item_number"></xsl:value-of>
    </td>
    <td width="13%" align="center" uniqueID="ms__id35">
        <xsl:value-of select="related_id[@type='Document']/Item/name"/>
    </td>
    <td width="8%" align="center" uniqueID="ms__id36">
        <xsl:value-of select="related_id[@type='Document']/Item/major_rev"/>
    </td>
 </tr>

Answer 1

使用模板。这样，在空案例中都没有应用：

<xsl:template match="Item[@type='Part AML']|Item[@type='Part Document']">
<tr>
    <xsl:apply-templates select="state"/>

    <xsl:apply-templates select="related_id[@type='Manufacturer Part']/Item/manufacturer/@keyed_name"/>

    <xsl:apply-templates select="related_id[@type='Manufacturer Part']/Item/item_number">

    <td width="13%" align="center" uniqueID="ms__id34">
        <xsl:value-of select="related_id[@type='Document']/Item/item_number"></xsl:value-of>
    </td>
    <td width="13%" align="center" uniqueID="ms__id35">
        <xsl:value-of select="related_id[@type='Document']/Item/name"/>
    </td>
    <td width="8%" align="center" uniqueID="ms__id36">
        <xsl:value-of select="related_id[@type='Document']/Item/major_rev"/>
    </td>
 </tr>
</xsl:template>

<xsl:template match="Item[@type='Part AML' or @type='Part Document']/state">
  <td width="5%" align="center" uniqueID="ms__id31">
     <xsl:apply-templates>
  </td>
</xsl:template>

<xsl:template match="Item[@type='Part AML' or @type='Part Document']/related_id[@type='Manufacturer Part']/Item/manufacturer/@keyed_name">
   <td width="13%" align="center" uniqueID="ms__id32">
     <xsl:apply-templates>
  </td>
</xsl:template>

<xsl:template match="Item[@type='Part AML' or @type='Part Document']/related_id[@type='Manufacturer Part']/Item/item_number">
   <td width="13%" align="center" uniqueID="ms__id33">
     <xsl:apply-templates>
  </td>
</xsl:template>

如果剩余的<td>可能也有空值，则可以使用相同的模式。

XSLT删除空白元素

1 个答案: