即使从服务器返回成功,我也收到了JSON parseerror。这是我的保存代码,其中始终运行fail()
@model.save()
.fail(=> @resetForm() )
.always (obj, error) ->
console.log obj
console.log obj.responseText
console.log JSON.parse(obj.responseText)
这是我的错误对象:
"parsererror"
"No conversion from text to http://api2.local/users/auth"
我在Jquery 1.8.3和Backbone 0.9.9上 服务器用json正确响应 - 这是我的响应头
Access-Control-Allow-Headers:origin, x-requested-with, content-type, accept
Access-Control-Allow-Methods:GET, POST, PUT, DELETE, OPTIONS
Access-Control-Allow-Origin:*
Access-Control-Max-Age:86400
Connection:Keep-Alive
Content-Length:202
Content-Type:application/json; charset=utf-8
Date:Fri, 21 Dec 2012 18:46:25 GMT
Keep-Alive:timeout=5, max=100
Server: xxx
X-Powered-By:PHP/5.3.1
console.log JSON.parse(obj.responseText)正确地给了我一个JSON对象
Accept:*/*
Accept-Charset:ISO-8859-1,utf-8;q=0.7,*;q=0.3
Accept-Encoding:gzip,deflate,sdch
Accept-Language:en-US,en;q=0.8
Cache-Control:no-cache
Connection:keep-alive
Content-Length:54
Content-Type:application/json
Host:api2.local
Origin:http://localhost:3000
Pragma:no-cache
Referer:http://localhost:3000/login
User-Agent:Mozilla/5.0 (Macintosh; Intel Mac OS X 10_6_8) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.101 Safari/537.11
X-Requested-With:XMLHttpRequest
{"email":"x@x.com","password":"xxx"}
{
"user_id":"xx",
"first_name":"xxx",
"last_name":"xxx",
"email":"x@x.com",
"role":"xxxx",
"date_joined":"xxx"
}
答案 0 :(得分:4)
啊啊 - 编程有时会非常恼人。最后想出来了 - 感谢大家的帮助,但这是一个简单的coffeescript编译问题
所以在我之前
$.ajaxPrefilter ( (options, originalOptions, jqXHR) ->
options.url = "#{ API_URL }" + options.url
)
编译返回options.url和$ .ajaxPrefilter。无论出于何种原因,Jquery在ajaxPrefilter函数中将options.url作为DataTypes argument。解决方案是返回false:
$.ajaxPrefilter \
(options, originalOptions, jqXHR) ->
options.url = "#{ API_URL }" + options.url
no
给出了正确的编译版本
return $.ajaxPrefilter(function(options, originalOptions, jqXHR) {
options.url = ("" + API_URL) + options.url;
return false;
});