Question

我似乎无法弄清楚为什么这不能正常工作。以下是设置的变量，但在“type”的最终结果中，它将其设置为m而不是fm

cpanel_notifications - 1
remote_server - 1

if ($_POST['cpanel_notifications'] == 1){
$type = "m";
}
elseif($_POST['cpanel_notifications'] == 0){
$type = "nm";
}
elseif($_POST['cpanel_notifications'] == 1 && $_POST['remote_server'] == 1){
$type = "fm";
}
elseif($_POST['cpanel_notifications'] == 0 && $_POST['remote_server'] == 0){
$type = "fnm";
}

结果：m

Answer 1

这是因为第一个if语句为真。没有理由去任何elses。

Answer 2

您需要做的是重新排序if's

if($_POST['cpanel_notifications'] == 1 && $_POST['remote_server'] == 1){
    $type = "fm";
}
elseif($_POST['cpanel_notifications'] == 0 && $_POST['remote_server'] == 0){
    $type = "fnm";
}
elseif ($_POST['cpanel_notifications'] == 1){
    $type = "m";
}
elseif($_POST['cpanel_notifications'] == 0){
    $type = "nm";
}

Answer 3

只需更改条件顺序

if ($_POST['cpanel_notifications'] == 1){
    if ($_POST['remote_server'] == 1) { 
        $type = "fm";
    } else {
        $type = "m";
    }
}
elseif($_POST['cpanel_notifications'] == 0){
    if ($_POST['remote_server'] == 0) {
        $type = "fnm";
    } else {
        $type = "nm";
    }
}

甚至

if ($_POST['cpanel_notifications'] == 1){
    $type = ($_POST['remote_server'] == 1?"fm":"m");
}
elseif($_POST['cpanel_notifications'] == 0){
    $type = ($_POST['remote_server'] == 0?"fnm":"nm");
}

Answer 4

我同意这些意见，指明将您的陈述更多地移动到多个条件。作为一般经验法则，您希望将最具体的语句放在最上面，并在条件列表中更加通用。

Answer 5

添加更多=

if ($_POST['cpanel_notifications'] === 1){
$type = "m";
}
elseif($_POST['cpanel_notifications'] === 0){
$type = "nm";
}
elseif($_POST['cpanel_notifications'] === 1 && $_POST['remote_server'] === 1){
$type = "fm";
}
elseif($_POST['cpanel_notifications'] === 0 && $_POST['remote_server'] === 0){
$type = "fnm";
}

http://php.net/manual/en/language.operators.comparison.php

以上链接显示了添加额外=符号的原因。

if，elseif不设置变量来设置正确的变量

5 个答案: