Question

我想要实现的是将字符串拆分为多个地址，例如“NL，VENLO，5928PN”，getLocation将返回“POINT（x y）”字符串值。

这很有效。接下来，我需要为每个位置创建一个WayPointDesc对象。并且每个对象都必须被推入WayPointDesc []。我尝试了各种方法，但到目前为止我找不到可行的选项。我最后的办法是硬编码最大数量的航点，但我宁愿避免这样的事情。

遗憾的是，使用列表不是一种选择......我想。

这是功能：

    /* tour()
     * Input: string route
     * Output: string[] [0] DISTANCE [1] TIME [2] MAP
     * Edited 21/12/12 - Davide Nguyen
     */
    public string[] tour(string route)
    {
        // EXAMPLE INPUT FROM QUERY
        route = "NL,HELMOND,5709EM+NL,BREDA,8249EN+NL,VENLO,5928PN"; 
        string[] waypoints = route.Split('+');

        // Do something completly incomprehensible
        foreach (string point in waypoints)
        {
            xRoute.WaypointDesc wpdStart = new xRoute.WaypointDesc();
            wpdStart.wrappedCoords = new xRoute.Point[] { new xRoute.Point() };
            wpdStart.wrappedCoords[0].wkt = getLocation(point);
        }

        // Put the strange result in here somehow
        xRoute.WaypointDesc[] waypointDesc = new xRoute.WaypointDesc[] { wpdStart };

        // Calculate the route information
        xRoute.Route route = calculateRoute(waypointDesc);
        // Generate the map, travel distance and travel time using the route information
        string[] result = createMap(route);
        // Return the result
        return result;

        //WEEKEND?
    }

Answer 1

数组是固定长度的，如果要动态添加元素，则需要使用某种类型的链表结构。此外，当您最初添加时，您的wpdStart变量超出了范围。

    List<xRoute.WaypointDesc> waypointDesc = new List<xRoute.WaypointDesc>();

    // Do something completly incomprehensible
    foreach (string point in waypoints)
    {
        xRoute.WaypointDesc wpdStart = new xRoute.WaypointDesc();
        wpdStart.wrappedCoords = new xRoute.Point[] { new xRoute.Point() };
        wpdStart.wrappedCoords[0].wkt = getLocation(point);

        // Put the strange result in here somehow
        waypointDesc.add(wpdStart);
    }

如果您确实希望以后将列表作为数组，请使用：waypointDesc.ToArray()

在foreach中创建对象以在C＃中推送到数组

1 个答案: