我一直在网上搜索几个小时,试图在C#中找到一个使用JSON调用进行序列化和反序列化的非常简单的例子。仔细浏览和拼凑后,我想在我的网络服务中调用JSON(POST& GET)函数(见下文)。
这是我能够拼凑的东西
这将是我的服务合同(IExecWebservice.svc)
using System.ServiceModel;
using System.ServiceModel.Web;
namespace _27963199
{
[ServiceContract]
public interface IExecFunction
{
[WebGet(UriTemplate = "/{function}/{args}")]
double CalcThis(string function, string args);
}
}
在我的主代码中,我解析出用户请求URI(IExecFunction.cs)
//user will send variables in REST URI http://myCalcServer/CalcThis/MethodA/10,20
using FunctionLibrary;
using System;
using System.Reflection;
namespace _27963199
{
public class ExecFunctionService : IExecFunction
{
public double CalcThis(string function, string args)
{
Type t = typeof(Functions);
MethodInfo[] libraryFunctions = t.GetMethods(BindingFlags.Static | BindingFlags.Public);
string[] arguments = args.Split(',');
//Missing piece of code where I split the URI for the JSON function that will POST the data object to be be calculated by the DROOLS/Rules Engine and the results passed back to the users web browser
...
}
}
}
现在在我的单独的函数类中,我有类似的东西(Function.cs)
using System;
using newton.json;
using System.Net.Http;
namespace FunctionLibrary
{
public static class Functions
{
public static double DoMathA(string url, string arg1, string arg2)
{
double d1;
double d2;
if (!double.TryParse(arg1, out d1) || !double.TryParse(arg2, out d2))
{
throw new ArgumentException("Arguments to function 'DoMathA' must be numeric.");
}
//Data Object Format "{'myData':{'Id':'5','var1':'10','var2':'90'}}"
myCalcObject = "{'myData':{'Id':'5', & arg1 & :'10', & arg2 & :'90'}}"
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
request.Method = "POST";
request.ContentType = "application/json; charset=utf-8";
DataContractJsonSerializer ser = new DataContractJsonSerializer(data.GetType());
MemoryStream ms = new MemoryStream();
ser.WriteObject (myCalcObject)
String json = Encoding.UTF8.GetString(ms.ToArray());
StreamWriter writer = new StreamWriter(request.GetRequestStream());
writer.Write(json);
writer.Close();
}
}
...
//Missing piece of code where I want to return the results of the JSON PUT and GET to the calling webservice
//JSON output string looks like this {"YourResults":{"condition":"YourHairIsOnFire","alertlevel":100,"id":0}}
//return or parse (json) to XLMS on the users browser
}
我需要填写空白的帮助,以便正确解析请求URI以传递到JSON函数,并在用户浏览器上将回复JSON字符串转换回xlms。有什么想法吗?
更新:我尝试将JSON部分作为一个独立的C#类工作,但我得到了#34;预期的课程......"编译时出错。
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Web;
using System.Net.Http;
using System.Net;
using Newtonsoft.Json;
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(http://172.16.20.26:8080/myDrools/result);
request.Method = "POST";
request.ContentType = "application/json; charset=utf-8";
DataContractJsonSerializer ser = new DataContractJsonSerializer(data.GetType());
MemoryStream ms = new MemoryStream();
ser.WriteObject ("{'myData':{'Id':'5','var1':'4.5','var2':'8.7'}}")
String json = Encoding.UTF8.GetString(ms.ToArray());
StreamWriter writer = new StreamWriter(request.GetRequestStream());
writer.Write(json);
writer.Close();
我在这里做错了什么?如何从中获取XMLS输出?
答案 0 :(得分:1)
你有几件零碎的东西。如果将它们粘在一起就可以了。
确保您的界面能够返回包含您希望返回的数据的对象。通过使字段可以为空,您可以对结果的变化有所不同。
请注意ResponseFormat=WebMessageFormat.Json
将json作为返回的内容类型。
[ServiceContract]
public interface IExecFunction
{
[WebGet(UriTemplate = "/{function}/{args}", ResponseFormat=WebMessageFormat.Json)]
[OperationContract]
Result CalcThis(string function, string args);
}
// the result class that actsd as an container
public class Result
{
public Double DoubleResult { get; set; }
public Int32 IntResult { get; set; }
public string Message { get; set; }
}
服务实现涉及更多,因为它首先需要解析参数并将它们转换为正确的类型。完成后,它可以使用反射来查找适当的调用方法。然后在Result
上转换/投影返回的类型。
public class ExecFunctionService : IExecFunction
{
// this is a GET /fubar/1,2,3,4
public Result CalcThis(string function, string args)
{
// function=fubar
// args = 1,2,3,4
var allargs = args.Split(',');
// store each argument with their type
var typeList = new List<Tuple<Type, object>>();
// parsr to gind the best match
foreach(var arg in allargs)
{
// convert each argument string
// to a type that is supported
int i;
if (Int32.TryParse(arg, out i))
{
typeList.Add(new Tuple<Type,object>(typeof(Int32), i));
continue;
}
double d;
if (Double.TryParse(arg,
NumberStyles.AllowDecimalPoint,
new CultureInfo("en-us"),
out d))
{
typeList.Add(new Tuple<Type,object>(typeof(Double), d));
continue;
}
// if all fails assume string
typeList.Add(new Tuple<Type,object>(typeof(string), arg));
}
// find and call the correct method
// notice that parameters and their type do matter
// overloads of the same methodname with
// different types is supported
// Functions is the static type with methods to call
var method = typeof(Functions).GetMethod(
function,
BindingFlags.Static| BindingFlags.Public |BindingFlags.InvokeMethod,
null,
typeList.Select(ty => ty.Item1).ToArray(), //all types
null);
var callresult = method.Invoke(
null,
typeList.Select(ty => ty.Item2).ToArray()); // all values
// shape the output in the form you need
var result = new Result();
if(callresult is double)
{
result.DoubleResult = (double) callresult;
}
if (callresult is int)
{
result.IntResult = (int)callresult;
}
if (callresult is string)
{
result.Message = (string)callresult;
}
return result;
}
}
这是包含可以从服务调用的所有方法的类。
// your calc functions go here
public static class Functions
{
public static double DoMathA(double arg1, double arg2)
{
return arg1 / arg2;
}
public static double DoMathB(int number, double factor)
{
return number * factor;
}
public static int DoMathC(string somestring)
{
return somestring.GetHashCode();
}
}
致电http://localhost/service1.svc/DoMathC/fubar
将返回:
{"DoubleResult":0,"IntResult":418978654,"Message":null}
和http://localhost/service1.svc/DoMathA/2.5,3.4
将返回:
{"DoubleResult":0.73529411764705888,"IntResult":0,"Message":null}
和http://localhost/service1.svc/DoMathB/4,3.5
将返回:
{"DoubleResult":14,"IntResult":0,"Message":null}
答案 1 :(得分:0)
这样想:不是试图将字符串粘在一起,而是返回一个对象。该服务将负责为您进行字符串化。 因此,创建一个具有与JSON对象匹配的属性的类,然后将值设置为这些属性,然后返回该对象。完成。 不要过分思考