Question

可能重复：
Iterar over array of entity and get value of some key based on value of “other key” matche

请问，如果状态字段不为空，那么任何人都可以给我一个关于如何获取字典中所有salary字段值的提示或提示吗？我只想从salary字典中的那些对象中检索status != null字段。请注意，我的字典是动态的，这意味着我可能有四个条目。任何帮助或提示高度赞赏。提前谢谢。

myArray=(
        {
        Name = "john1";
        Address = "san diego";
        Status = "active";
        salary = "100;

    },
        {
        Name = "steve ";
        Address = "birmingham";
        Status = "<null>";
        salary = "100;
    },
        {
         Name = "allan";
        Address = "san diego";
        Status = "active";
        salary = "100;
    },

     {
         Name = "peter";
        Address = "san diego";
        Status = "<null>";
        salary = "100;
    },
)

Answer 1

尝试快速枚举...

NSMutableArray* retreivedSalaries;

for (NSDictionary* dict in myArray) {
    if (![[dict objectForKey:@"Status"] isEqualToString:@"<null>"])
        [retreivedSalaries addObject:[dict objectForKey:@"salary"]];
 };

Answer 2

我没有测试过，所以你可能需要改变这个

for (int i=0;i< [myArray count];i++)
{
    if ([[[myArray objectAtIndex: i] objectForKey: @"Status"] isEqualToString: @"active"]) {

       NSLog(@"Salary is %@",[myArray objectAtIndex: i] objectForKey: @"salary"] )
    } else {
        NSLog(@"Status is not active");
    }
}

或者你可以使用这样的东西

  for (NSDictionary *salary in myArray)
    {
        if([message valueForKey:@"Status"] isEqualToString: @"active")
           NSLog(@"Salary is %@",[message valueForKey:@"salary"]);      

    }

排序薪水

您可以对键进行排序，然后通过迭代来创建NSMutableArray。 answer from here

NSArray *sortedKeys = [[myArray allKeys] sortedArrayUsingSelector: @selector(compare:)];
NSMutableArray *sortedValues = [NSMutableArray array];
for (NSString *key in sortedKeys)
    [sortedValues addObject: [myArray objectForKey: key]];

Answer 3

试试这个：

  NSDictionary *salaries = nil;
  NSArray *myArray .... ;


for (NSString * salary in salaries) {

    if ([myArray containsObject:@"salary"]) {

        if ([salaries objectForKey:@"salary"] != NULL) {

            NSLog (@"do something with salary: %@", salary);
        }
    }

}

Answer 4

我认为这是iOS，myArray是一个NSArray，每个dinamically人信息都是NSDictionary，如果这是重点，你可以做到以下几点：

for (NSDictionary *info in myArray) {

    if ([info objectForKey:@"Status"] != nil && ![[info objectForKey:@"Status"] isEqual:@"<null>") {
        // Store salary whatever you need and in the formar you need
        NSString *salary = [info objectForKey:@"salary"]; 
    }

}

我没有编译器编写代码，所以也许有一些编译器错误（抱歉）。如果我很清楚你的问题，那么当状态不为空时，你可以获得工资。

希望帮助！

根据其他字段的值，有条件地从字典中检索字段

4 个答案: