每隔几秒就在HTML页面中更改图像

时间:2012-12-20 15:55:53

标签: javascript html image timer

我想每隔几秒更换一次图片,这是我的代码:

<?xml version = "1.0" encoding = "utf-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
   "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">

<html xmlns = "http://www.w3.org/1999/xhtml">
   <head>
      <title>change picture</title>
      <script type = "text/javascript">

    function changeImage()
    {
    var img = document.getElementById("img");
    img.src = images[x];
    x++;

    if(x >= images.length){
        x = 0;
    } 
   var timerid = setInterval(changeImage(), 1000);
}   }
var images = [], x = 0;
images[0] = "image1.jpg";
images[1] = "image2.jpg";
images[2] = "image3.jpg";

      </script>
   </head>
   <body onload = "changeImage()">
 <img id="img" src="startpicture.jpg">
   </body>
</html>

我的问题是它停留在第一张照片上!

我还想尝试使用上一个和下一个按钮翻看图片,但我不知道该怎么做。

6 个答案:

答案 0 :(得分:26)

正如我在评论中发布的那样,您不需要同时使用setTimeout()setInterval(),而且您也会遇到语法错误(额外的})。像这样纠正你的代码:

(编辑添加两个函数以强制显示下一个/上一个图像)

<!DOCTYPE html>

<html>
   <head>
      <title>change picture</title>
      <script type = "text/javascript">
          function displayNextImage() {
              x = (x === images.length - 1) ? 0 : x + 1;
              document.getElementById("img").src = images[x];
          }

          function displayPreviousImage() {
              x = (x <= 0) ? images.length - 1 : x - 1;
              document.getElementById("img").src = images[x];
          }

          function startTimer() {
              setInterval(displayNextImage, 3000);
          }

          var images = [], x = -1;
          images[0] = "image1.jpg";
          images[1] = "image2.jpg";
          images[2] = "image3.jpg";
      </script>
   </head>

   <body onload = "startTimer()">
       <img id="img" src="startpicture.jpg"/>
       <button type="button" onclick="displayPreviousImage()">Previous</button>
       <button type="button" onclick="displayNextImage()">Next</button>
   </body>
</html>

答案 1 :(得分:4)

下面的

将每10秒更改一次链接和横幅

   <script>
        var links = ["http://www.abc.com","http://www.def.com","http://www.ghi.com"];
        var images = ["http://www.abc.com/1.gif","http://www.def.com/2.gif","http://www.ghi.com/3gif"];
        var i = 0;
        var renew = setInterval(function(){
            if(links.length == i){
                i = 0;
            }
            else {
            document.getElementById("bannerImage").src = images[i]; 
            document.getElementById("bannerLink").href = links[i]; 
            i++;

        }
        },10000);
        </script>



<a id="bannerLink" href="http://www.abc.com" onclick="void window.open(this.href); return false;">
<img id="bannerImage" src="http://www.abc.com/1.gif" width="694" height="83" alt="some text">
</a>

答案 2 :(得分:2)

setTimeout("changeImage()", 30000);更改为setInterval("changeImage()", 30000);并移除var timerid = setInterval(changeImage, 30000);

答案 3 :(得分:2)

截至目前编辑的帖子版本,您可以在每次更改结束时致电setInterval添加新的&#34;更换器&#34;每次新的iterration 。这意味着在第一次运行之后,其中一个在内存中打勾,经过100次运行后,100个不同的转换器每秒更换图像100次,完全破坏性能并产生令人困惑的结果。

你只需要&#34; prime&#34; setInterval一次。将其从函数中删除并将其放在onload内而不是直接函数调用。

答案 4 :(得分:1)

您可以在开头加载图像并更改css属性以显示每个图像。

var images = array();
for( url in your_urls_array ){
   var img = document.createElement( "img" );
   //here the image attributes ( width, height, position, etc )
   images.push( img );
}

function player( position )
{
  images[position-1].style.display = "none" //be careful working with the first position
  images[position].style.display = "block";
  //reset position if needed
  timer = setTimeOut( "player( position )", time );
}

答案 5 :(得分:0)

使用带有左侧垂直可点击缩略图的javascript交换图像的最佳方式

脚本文件:     function swapImages(){

    window.onload = function () {
        var img = document.getElementById("img_wrap");
        var imgall = img.getElementsByTagName("img");
        var firstimg = imgall[0]; //first image
        for (var a = 0; a <= imgall.length; a++) {
            setInterval(function () {
                var rand = Math.floor(Math.random() * imgall.length);
                firstimg.src = imgall[rand].src;
            }, 3000);



            imgall[1].onmouseover = function () {
                 //alert("what");
                clearInterval();
                firstimg.src = imgall[1].src;


            }
            imgall[2].onmouseover = function () {
                clearInterval();
                firstimg.src = imgall[2].src;
            }
            imgall[3].onmouseover = function () {
                clearInterval();
                firstimg.src = imgall[3].src;
            }
            imgall[4].onmouseover = function () {
                clearInterval();
                firstimg.src = imgall[4].src;
            }
            imgall[5].onmouseover = function () {
                clearInterval();
                firstimg.src = imgall[5].src;
            }
        }

    }


}
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