我希望通过将扩展类型作为参数来删除文件夹中的文件扩展名。
下面是我的代码,它没有按照我的预期工作。
if [ $# -ne 1 ]
then
echo -e "\nUsage: $0 Ext"
echo -e "\nExt - Refers to the extension you want to remove"
echo -e "\nExample1: $0 .txt\nExample2: $0 .doc\nExample3: $0 .pdf\n"
exit 1
fi
ext=$1
for i in *$ext
do
echo $i
filename=${i%\$ext}
echo $i
done
答案 0 :(得分:0)
您的代码几乎是正确的,但您需要删除转义并回显文件名。下面的代码还显示了basename的使用:
for i in *$ext
do
echo $i
filename1=${i%$ext}
filename2=$(basename $i $ext)
echo $filename1
echo $filename2
done
答案 1 :(得分:0)
您可以使用此脚本替换扩展程序
#!/bin/bash
if [ $# -ne 1 ]
then
echo -e "\nUsage: $0 Ext"
echo -e "\nExt - Refers to the extension you want to remove"
echo -e "\nExample1: $0 .txt\nExample2: $0 .doc\nExample3: $0 .pdf\n"
exit 1
fi
ext=$1
for i in *$ext
do
echo $i
new_name=`echo $i | sed 's/.'$ext'//g'`
echo $new_name
done
答案 2 :(得分:0)
您可以使用以下代码:
#!/bin/bash
if [ $# -ne 1 ]
then
echo -e "\nUsage: $0 Ext"
echo -e "\nExt - Refers to the extension you want to remove"
echo -e "\nExample1: $0 .txt\nExample2: $0 .doc\nExample3: $0 .pdf\n"
exit 1
fi
ext=$1
for i in *$ext
do
echo $i
new_name=`echo $i |rev|cut -d'.' -f2-|rev
echo $new_name
done