Question

我该怎么做？

File myFile = getFile(this.getClass.getResourceAsStream("test.txt"))

OR

File myFile = getFile(this.getClass.getResource("test.txt"))

我将在getFile()方法中编写哪些代码？

Answer 1

这是功能：

public File getFile(FileInputStream inStream){

File file =new File("file.txt");
OutputStream outStream = null;
outStream = new FileOutputStream(file);

byte[] buffer = new byte[1024];

            int length;
            //copy the file content in bytes 
            while ((length = inStream.read(buffer)) > 0){

                outStream.write(buffer, 0, length);

            }


            outStream.close();

return file;

}

Answer 2

哟可以这样做

    File f = new File(this.getClass().getResource("test.txt").toURI());
    System.out.println(f);

输出（我的Eclipse测试）

D:\workspace1\x\target\classes\text.txt

但它总是不起作用。如果你的资源在一个罐子里怎么办？你会得到

 java.lang.IllegalArgumentException: URI is not hierarchical

将资源/流转换为文件

2 个答案: