Question

我的页面构造函数中包含此代码：

    private String selectedAwsId;
    private String selectedIsReal;
    //these two are actually outside the constructor, and getters and setters for these two strings not shown

    List<AwsCredentials> awsCredentials = (List<AwsCredentials>)getAwsCredentials();
    List<String> awsIds = new ArrayList<String>();
    for (AwsCredentials cred : awsCredentials){
        awsIds.add(cred.getAwsId());
    }
    selectedAwsId = awsIds.get(0);

    List<String> yesOrNo = Arrays.asList(new String[] { "sandbox", "real"});
    selectedIsReal = "sandbox";

    Form selectAwsCredentialsForm = new Form("selectAwsCredentialsForm"){
        @Override
        public void onSubmit() {
            super.onSubmit(); 
            //TODO: why isn't this updating the form?
        }
    };
    add(selectAwsCredentialsForm);
    selectAwsCredentialsForm.add(new DropDownChoice("selectAwsCredentialsDropdown", new PropertyModel(this, "selectedAwsId"), awsIds));
    selectAwsCredentialsForm.add(new DropDownChoice("selectRealOrSandboxHitsDropdown", new PropertyModel(this, "selectedIsReal"), yesOrNo));

我第一次渲染页面时，这很好用。但是，当我在DropDownChoices中的任何一个中更改选择并提交表单时，页面不会更改（selectedAwsId和selectedIsReal中的值不会相应地更改）。在理解表格如何运作时，我是否缺少一些东西？提交表单时是否刷新整个页面（构造函数是否再次运行？）

Answer 1

您可能想要构建模型并将其设置为表单的模型。（这就是我所做的。）提交表单（如果所有表格都已正确编码）将导致表格的模型更新。

Wicket在表单提交后不更新页面

1 个答案: