Question

我在C＃代码中遇到问题：

我不知道如何实现逻辑 - 迭代Hashtable 拥有不同数据类型的值，我想要的架构如下：

if the value in variable is String type
{
 do action1;
}
else 
{
  do action2;
}

有一个包含Types - String和Int（组合）数据的哈希表：

public string SQLCondGenerator {

        get
        {

            Hashtable conditions = new Hashtable();

            //data having String data type
            conditions.Add("miap", ViewState["miap_txt"]);
            conditions.Add("pocode", ViewState["po_txt "]);
            conditions.Add("materialdescription", ViewState["mat_desc_txt"]);
            conditions.Add("suppliername", ViewState["supplier_txt"]);
            conditions.Add("manufacturername", ViewState["manufacturer_txt"]);

            //data having Int32 data type
            conditions.Add("spareparts", ViewState["sp_id"]); 
            conditions.Add("firstfills", ViewState["ff_id"]);
            conditions.Add("specialtools", ViewState["st_id"]);
            conditions.Add("ps_deleted", ViewState["ps_del_id"]);
            conditions.Add("po_manuallyinserted", ViewState["man_ins_id"]);

            String SQLCondString = "";
            String SQLCondStringConverted = "";


            string s = string.Empty;
            foreach (string name in conditions.Keys) 
            {
                if (conditions[name] != null)
                {
                    SQLCondString += name+ "=" +conditions[name]+ " and ";
                    Response.Write(conditions[name].GetType());

                    bool valtype = conditions[name].GetType().IsValueType;
                    if (valtype == string)
                    {
                      SQLCondString.Substring(0, SQLCondString.Length - 4);
                      SQLCondString += name + " and like '%" + conditions[name] + "%' and ";
                    }
                }
            }

        //Response.Write("********************");
         SQLCondStringConverted = SQLCondString.Substring(0, SQLCondString.Length - 4);
         return SQLCondStringConverted;
        }   
    }

可能是我编码错了，请指教！

谢谢！

Answer 1

if(conditions[name] is string)
{
}
else
{
}

Answer 2

嗯，我不确定你为什么打电话给IsValueType，但这应该足够了：

if (conditions[name] is string) 
{
    ///  
}

Answer 3

方法 - 1

Int32 Val = 0;
if (Int32.TryParse("Your Value", out Val))
{
    //Your Logic for int
}
else
{
    //Your Logic for String
}

方法 - 2（使用后期绑定）

Int32 Val = 0;
dynamic conditions = new Hashtable();
conditions.Add("miap", ViewState["miap_txt"]);
conditions.Add("pocode", ViewState["po_txt "]);
foreach (string name in conditions.Keys)
{
    if (Int32.TryParse(conditions[name].ToString(), out Val))
    {
        //Your Logic for int
    }
    else
    {
        //Your Logic for String
    }
}

Answer 4

我遇到了同样的问题，但是我使用的是textBoxes，需要验证输入的内容是字母，-还是。

我在textBox上生成了一个按键事件，并插入了以下方法来检查每个按键并在其无效字符时给出提示：

public static class Validator
{
public static bool IsNameString(TextBox tb, string name, KeyPressEventArgs e)
    {
        bool valid = true;

        /*  e.KeyChar contains the character that was pressed
         e.Handled is a boolean that indicates that handling is done            
        if a bad character is entered, set e.Handled to true
        */
        if (!char.IsLetter(e.KeyChar) && e.KeyChar != ' ' && e.KeyChar != '-' &&
          e.KeyChar != '.' && e.KeyChar != (char)Keys.Back)
        {
            e.Handled = true;
            valid = false;
            MessageBox.Show(name+ " can only accept letters, space, - and .");
            tb.Focus();

        }
        return valid;
    }
}

用法：

 private void txtCustomerName_KeyPress(object sender, KeyPressEventArgs e)
    {            
       Validator.IsNameString(txtCustomerName, "Customer Name", e);

    }

检查var是否为String类型

4 个答案:

方法 - 1

方法 - 2（使用后期绑定）