Question

以下代码显示订购产品的个别重量：

$weightsql = 'select op.products_name, op.products_quantity , p.products_weight from ' . TABLE_ORDERS_PRODUCTS . ' op left join ' . TABLE_PRODUCTS . ' p on op.products_id = p.products_id where op.products_id =  '.$pro['products_id'];

$weightq = tep_db_query( $weightsql );

while ($weight = tep_db_fetch_array( $weightq )){

        if($category_parent_id != 0)$list_items[] = $weight['products_weight'].'&nbsp;&nbsp;&nbsp;';

}

这显示了订购的每种产品的重要性。我坚持的不是显示单独的重量，而是需要显示总重量。例如，如果产品订购了三次，重量为7kg，那么目前的代码显示：

Product                   7.00  7.00  7.00

如何让它显示21公斤的总重量？

Answer 1

使用array_sum()

array_sum() examples
<?php
$a = array(2, 4, 6, 8);
echo "sum(a) = " . array_sum($a) . "\n";

$b = array("a" => 1.2, "b" => 2.3, "c" => 3.4);
echo "sum(b) = " . array_sum($b) . "\n";
?>
The above example will output:
sum(a) = 20
sum(b) = 6.9

Answer 2

在循环之前将计数器设置为0并在循环期间添加它，如下所示：

 $total = 0;
 $weightsql = 'select op.products_name, op.products_quantity , p.products_weight from ' . TABLE_ORDERS_PRODUCTS . ' op left join ' . TABLE_PRODUCTS . ' p on op.products_id = p.products_id where op.products_id =  '.$pro['products_id'];

 $weightq = tep_db_query( $weightsql );

 while ($weight = tep_db_fetch_array( $weightq )){
      if($category_parent_id != 0) {
           $list_items[] = $weight['products_weight'].'&nbsp;&nbsp;&nbsp;';
           $total += $weight['products_weight'];
      }

 }

变量$ total应该返回21。

Answer 3

如果您按照ID选择了产品，最简单的解决方案是将行数乘以权重。无需将其放入数组中。

Answer 4

$weightsql = 'select op.products_name, sum(op.products_quantity * p.products_weight) as weightsum from ' . TABLE_ORDERS_PRODUCTS . ' op left join ' . TABLE_PRODUCTS . ' p on op.products_id = p.products_id where op.products_id =  '.$pro['products_id'];


echo $weight['weightsum']

感谢您的帮助（！）

PHP数组的总和

4 个答案: