我希望通过比较u.fld_id = ct.fld_teacher_id
来获取教师的信息
如果ct.fld_teacher_id为null,我将显示尚未分配。但是具有null ct.fld_teacher_id的行在执行时不会显示。
这是我的查询。
SELECT ct.fld_id as id, ct.fld_serial, ct.fld_city, ct.fld_venue_name,
ct.fld_start_time, ct.fld_end_time,
ct.fld_duration, ct.fld_available_seats,
ct.fld_course_price, ct.fld_status,
c.fld_name, u.fld_first_name, u.fld_last_name,
ct.fld_status, ct.fld_teacher_id, ct.fld_training_name,
ct.fld_class, ct.fld_level, ct.fld_is_fixed, tt.fld_name as training_type_name
FROM tbl_course_training as ct, tbl_users as u,
tbl_courses as c, tbl_training_types as tt
WHERE c.fld_id = ct.fld_course_id AND u.fld_id = ct.fld_teacher_id AND
ct.fld_teacher_id = 'NULL' AND tt.fld_id = ct.fld_training_type_id