我有两个数组,我只想从第二个数组中提取值,只要它的键与第一个数组键匹配。
我的第一个数组是
[deal_id] => Array
(
[0] => Array
(
[0] => 75
[5] => 76
[10] => 77
[15] => 79
)
[1] => Array
(
[0] => 84
)
[2] => Array
(
[0] => 86
[3] => 88
[8] => 89
)
[3] => Array
(
[0] => 97
)
[4] => Array
(
[0] => 100
[4] => 104
)
)
我的第二个数组是
[package_id] => Array
(
[0] => Array
(
[0] => 10
[1] => 75
[2] => 75
[3] => 75
[4] => 75
[5] => 67
[6] => 34
[7] => 89
[10] => 04
[15] => 75
)
[1] => Array
(
[0] => 10
[1] => 29
[2] => 34
[3] => 45
)
[2] => Array
(
[0] => 12
[3] => 23
[4] => 45
[5] => 76
[6] => 87
[8] => 45
)
[3] => Array
(
[0] => 34
[1] => 54
[2] => 34
)
[4] => Array
(
[0] => 145
[1] => 143
[6] => 146
[4] => 344
)
)
预期产出:
[package_id] => Array
(
[0] => Array
(
[0] => 10
[5] => 67
[10] => 04
[15] => 75
)
[1] => Array
(
[0] => 10
)
[2] => Array
(
[0] => 12
[3] => 23
[8] => 45
)
[3] => Array
(
[0] => 34
)
[4] => Array
(
[0] => 145
[4] => 344
)
)
我只想要第二个数组中那些键匹配第一个数组的值。我希望我的第二个数组看起来与我的第一个数组完全相同,除了值。
由于
答案 0 :(得分:0)
我认为最好用一些for循环来完成。效率不高,但据我所知,没有真正的自动化方式。
我不确定这是否正是你想要的,但它可能是一个开始。所以不要只是复制过去的代码(因为它可能不会工作,因为它没有经过测试),但也许这对你自己的代码来说是一个好的开始。
for($arr1 as $key11 => $val11){
if(isset($arr2[$key11])){
$contains = false;
for($val11 as $key12 => $val12){
if(isset($arr2[$key11][$key12]){
// Contains
$contains = true;
}
}
if(!$contains){
// Doesn't contain
}
}
}
答案 1 :(得分:0)
我尝试将您的数组复制到此:
$deal = array(
array(
0=>75, 5=>76, 10=>77, 15=>79,
),
array(
0=>84,
),
array(
0=>86, 3=>88, 8=>89,
),
);
$package = array(
array(
0=>10, 1=>75, 2=>75, 3=>75, 4=>75, 5=>67, 6=>34, 7=>89, 10=>04, 15=>75,
),
array(
0=>10, 1=>29, 2=>34, 3=>45,
),
array(
0=>12, 3=>23, 4=>45, 5=>76, 6=>87, 8=>45,
),
);
并使用此代码段处理它:
$result = array();
foreach($deal as $key => $value){
foreach($value as $key2 => $value2){
if(array_key_exists($key2, $package[$key])){
if(!isset($key, $result)){
$result[$key] = array();
}
$result[$key][$key2] = $package[$key][$key2];
}
}
}
注意:这里的真正诀窍是,使用array_key_exists()检查
$package
数组中是否存在相关密钥。
得到以下结果:
Array
(
[0] => Array
(
[0] => 10
[5] => 67
[10] => 4
[15] => 75
)
[1] => Array
(
[0] => 10
)
[2] => Array
(
[0] => 12
[3] => 23
[8] => 45
)
)
答案 2 :(得分:0)
感谢大家的帮助。从上面的建议中获取线索。我终于得到了答案。
这是工作代码:
foreach ($deal_ids as $dealkey => $dealval) {
foreach ($dealval as $dkey => $dval) {
foreach ($deal_duration as $dukey => $duval) {
foreach ($duval as $deukey => $deuval) {
if ($dkey == $deukey) {
$dur[$dealkey][$deukey] = $deuval;
}
}
}
}
}
答案 3 :(得分:0)
只需使用此array_intersect_key循环到一个小的数组。