Question

我在我的网页上使用谷歌标记。使用PHP页面从数据库中获取纬度，经度，名称和详细信息，然后使用$ .post方法在jquery上使用它。

<?php 

//Basic environment setup (error handling and logging, cookies/sessions, php directives         etc)
require_once $_SERVER['DOCUMENT_ROOT'] . '/../Config/path_config.php';
require_once C_PATH_UTILITY_MANAGER_PAGESETUP;
Page_Setup_Manager::setDefaultPageSettings();

require_once C_DIR_UTILITY_EVENTS_DATAACCESS;

$eventsdats=Eventsdata::getevents();
$temp=array();


foreach($eventsdats as $singlemapevent)
{
array_push($temp,array($singlemapevent['ename'],
     (floatval($singlemapevent['latitude'])),
    (floatval($singlemapevent['longitude'])),
    ($singlemapevent['edate']),
    ($singlemapevent['etime']),
    ($singlemapevent['edetail'])
    ));
}
echo json_encode($temp);

//Result[["Second Event",19.0554748,72.8497017,"17-12-2012","17:57 ","This is the  

social detail;"],["Demo Event",19.2097381,72.8737017,"08-12- 2012","09:34 ","This event  

was held in bhayander by ganesh mandhre"],]
?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"     

"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<meta name="viewport" content="initial-scale=1.0, user-scalable=no" />
<script type="text/javascript" src="http://maps.google.com/maps/api/js?sensor=false">    

</script>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<script type="text/javascript">


function initialize() {
    markers=[];
    temp=[];
    final_markers=[];
    $.post('maps_data.php',{},function(data){

       },"json").done(function(data){
           markers=(data);
           $.each(data,function(index,value){


            final_markers.push($.makeArray(value));

               });
           markers=final_markers;

       });
    alert(markers);
    var latlng = new google.maps.LatLng(19.0554748, 72.8497017);
    var settings = {
        zoom: 10,
        center: latlng,
        visible:true,
        mapTypeControl: true,
        mapTypeControlOptions: {style:   

google.maps.MapTypeControlStyle.DROPDOWN_MENU},
        navigationControl: true,
        navigationControlOptions: {style: 

google.maps.NavigationControlStyle.SMALL},
        mapTypeId: google.maps.MapTypeId.ROADMAP
        };
        var map = new 
google.maps.Map(document.getElementById("map_canvas"), settings);


        var infowindow = new google.maps.InfoWindow(), marker, i;
        for (i = 0; i < markers.length; i++) {  


            marker = new google.maps.Marker({
                position: new google.maps.LatLng(markers[i][1], markers[i][2]),
                map: map
            });

            google.maps.event.addListener(marker, 'click', (function(marker, i) {
                return function() {
                    var contentString = '<div id="content">'+
                    '<div id="siteNotice">'+
                    '</div>'+
                    '<h1 id="firstHeading"  class="firstHeading">'+markers[i][0]+'</h1>'+
                    '<div id="bodyContent">'+
                    '<p>'+markers[i][3]+'</p>'+
                    '<p>'+markers[i][4]+'</p>'+
                    '<p>'+markers[i][5]+'</p>'+
                    '</div>'+
                    '</div>';

                    infowindow.setContent(contentString);
                    infowindow.open(map, marker);
                }
            })(marker, i));
        }
    }
</script>
<title>Untitled Document</title>
</head>
<body onload="initialize()">
<div id="map_canvas" style="width:100%; height:350px"></div>
</body>
</html>

标记在firefox中可见，但在chrome和safari中不可见。错误是什么？我错误地使用了json吗？

Answer 1

获取json数据时，必须在回调中处理它们。在此处显示ajax调用完成之前的地图和标记。将此呈现移至done回调。

谷歌地图标记没有显示在chrome和safari ..在Stackoverflow上的所有答案

1 个答案: