我认为我部分工作,但由于某种原因,它没有得到文章的内容..
<?php
$amount_get = mysql_query("SELECT * FROM comment WHERE articleid='" . mysql_real_escape_string($_GET['id']) . "'");
$comments = mysql_num_rows($amount_get);
$grab = mysql_query("SELECT * FROM articles WHERE id='" . mysql_real_escape_string($_GET['id']) . "' LIMIT 1");
$grab = mysql_query("SELECT id, news_title, news_content, news_author, news_day, news_month, news_year, news_date FROM articles ORDER BY id DESC limit 3");
$news_day =$row['news_day'];
$news_month =$row['news_month'];
$news_year =$row['news_year'];
if (mysql_num_rows($grab)==0) {
echo "<div class='alert alert-note-x'>Sorry, it looks like their are no articles posted!</div>";
}
else if(strlen($row['news_contents']) > 135) {
$news_content = substr($news_content, 0, 135) . "....";
}
while($row = mysql_fetch_array($grab)){
?>
<div class="post-container">
<div class="post">
<div class="left">
<div class="date"><span class="day"><?php echo $row['news_day'] ?></span> <span class="month"><?php echo $row['news_month'] ?></span> <span class="year"><?php echo $row['news_year'] ?></span></div></div>
<div class="postcontent"><h5 class="posttitle"><a href="#/media/<?php echo $row['id'] ?>.<?php echo stripslashes(str_replace(" ", "-", $row['news_title'])); ?>"><?php echo stripslashes($row['news_title']); ?></a></h5>
<?php echo (strlen($row['news_content']) > 135); ?>
</div>
</div>
</div>
<?php } ?>
这就是它的样子:http://puu.sh/1CD32
你们知道为什么它会显示“1”而不是数据库中的内容吗?
<?php echo (strlen($row['news_content']) > 135); ?>
答案 0 :(得分:3)
你要求它打印表达式的结果“(strlen($ row ['news_content'])&gt; 135)”如果字符串超过135个字符,则为1(如真) (如在假的情况下),如果没有。
答案 1 :(得分:1)
你问的是变量$ row ['news_content']是否大于135个字符。它将打印1表示true,0表示false。
如果您正在尝试打印变量的前135个字符,那么您正在寻找substr而不是strlen
echo substr($row['news_content'], 0, 135);
答案 2 :(得分:0)
因此:
<?php echo (strlen($row['news_content']) > 135); ?>
这是返回真或假
在1
中回显true结果和false将为空