无法在Python中捕获异常IndexError?

时间:2012-12-19 03:05:35

标签: python exception

这是我想要抓住的错误:

 Traceback:
    File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py" in get_response
      111.                         response = callback(request, *callback_args, **callback_kwargs)
    File "/opt/django/fileupload/views.py" in upload_file
      56.         folder_info = url.split(':')[1] #Extracts folder info to use in the header

    Exception Type: IndexError at /upload_file/
    Exception Value: list index out of range

尝试使用:

except (socket.error, paramiko.AuthenticationException, IndexError):
            return render_to_response('reform.html', context_instance=RequestContext(request))

但它不起作用。

我能够捕获socket.errorparamiko.Authentication例外,而不是IndexError。我试图在Django中捕获异常。感谢。

修改: 整个尝试和除块:

try:        
    source = str(username) + "@" + url #Source to list all the files
    add_key = str(username) + "@" + test_url
    add_known_hosts(password, add_key) #Add to the known hosts
    test_ssh(test_url, username, password) #Test Host_name, username and password
    destination = '/home/sachet/files'    
    command = subprocess.Popen(['sshpass', '-p', password, 'rsync', '--recursive', source],
                   stdout=subprocess.PIPE).communicate()[0] #sshpass needs to be installed into the server
    lines = (x.strip() for x in command.split('\n'))
    remote = [x.split(None, 4)[-1] for x in lines if x] #Removes permission from the file listing
    base_name = [os.path.basename(ok) for ok in remote]
    result = subprocess.Popen(['ls', destination], stdout=subprocess.PIPE).communicate()[0].splitlines()

    return render_to_response('thanks.html', {'res1': remote, 'res': result, 'folder': folder_info}, context_instance=RequestContext(request))
except (socket.error, paramiko.AuthenticationException, IndexError):
    return render_to_response('reform.html', context_instance=RequestContext(request)) 

1 个答案:

答案 0 :(得分:1)

在您发布的try / except块中未引发IndexError。 IndexError在分配了folder_info的行上引发(views.py中的第56行)。您需要将该行代码移动到try / except块中以捕获该错误。

File "/opt/django/fileupload/views.py" in upload_file
    56.         folder_info = url.split(':')[1]  <-- This line

或者,更好的是,在“folder = ...”行周围添加一个单独的try / except,仅用于IndexError,以使代码的意图更清晰。